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A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the

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Re: A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the  [#permalink]

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New post 04 Aug 2014, 21:19
Bunuel wrote:
bhanuvemula wrote:
A sequence, a1=64, a2=66, a3=67, an=8+an-3, which of the following is in the sequence?

105
786
966
1025

can any one help me with this.
:thanks Bhanu


Easier way would be to write down several terms from the sequence:
\(a_1 = 64\)
\(a_2 = 66\)
\(a_3 = 67\)

\(a_4 = 8 + a_1 = 72\)
\(a_5 = 8 + a_2 = 74\)
\(a_6 = 8 + a_3 = 75\)
...
\(a_n = 8 + a_{n - 3}\)

Note that the terms in the sequence have remainder of 0 (\(a_1\), \(a_4\), \(a_7\), ...), 2 (\(a_2\), \(a_5\), \(a_8\), ...) or 3 (\(a_3\), \(a_6\), \(a_9\), ...) upon division by 8. Only 786 has appropriate remainder of 2 (105 and 1025 has a remainder of 1 upon division by 8 and 966 has a remainder of 6).

Answer: B.

Hope it's clear.


Thanks for your exp. I think your solution is the best and shortest way to reach the answer.
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Re: A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the  [#permalink]

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New post 29 Mar 2017, 09:19
bhanuvemula wrote:
A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the following is in the sequence?

A. 105
B. 786
C. 966
D. 1025


We should deduct 64 / 66 / 67 from answers and then look for a number that is multiple of 8

PS: please add one more wrong answer choise E to make this question looks like GMAT question
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Re: A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the  [#permalink]

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New post 29 Mar 2020, 14:01
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Re: A sequence, a1=64, a2=66, a3=67, an=8+a(n-3), which of the   [#permalink] 29 Mar 2020, 14:01

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