|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
14 Jul 2021, 04:45
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:15) correct
7%
(02:14)
wrong
based on 108
sessions
History
Date
Time
Result
Not Attempted Yet
A sequence is defined as \(a_n = 5(a_{n - 1}) - 3\) where \(a_4 = 32\). What is the first term of the sequence, \(a_1\)?
(A) 1
(B) 7
(C) 16
(D) 128
(E) 157
(A) 1
(B) 7
(C) 16
(D) 128
(E) 157
14 Jul 2021, 06:15
Kudos
Bookmarks
\(a_n = 5(a_{n - 1}) - 3\)
\(a_4 = 32 = 5(a_{3}) - 3 [n - 1 = 4 - 1 = 3]\)
=> \(32 + 3 = 5a_3\)
=> \(a_3 = 7\)
\(a_3 = 7 = 5(a_{2}) - 3 [n - 1 = 3 - 1 = 3] \)
=> \( 7 + 3 = 5a_2\)
=> \(a_2 = 2\)
\(a_2 = 2 = 5(a_{1}) - 3 [n - 1 = 3 - 1 = 3] \)
=> \(2 + 3 = 5a_1\)
=> \(a_1 = 1\)
Answer A
\(a_4 = 32 = 5(a_{3}) - 3 [n - 1 = 4 - 1 = 3]\)
=> \(32 + 3 = 5a_3\)
=> \(a_3 = 7\)
\(a_3 = 7 = 5(a_{2}) - 3 [n - 1 = 3 - 1 = 3] \)
=> \( 7 + 3 = 5a_2\)
=> \(a_2 = 2\)
\(a_2 = 2 = 5(a_{1}) - 3 [n - 1 = 3 - 1 = 3] \)
=> \(2 + 3 = 5a_1\)
=> \(a_1 = 1\)
Answer A
