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A sequence of consecutive integers begins with 60 and ends with 100.

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A sequence of consecutive integers begins with 60 and ends with 100.  [#permalink]

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29 Mar 2018, 23:39
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15% (low)

Question Stats:

85% (00:42) correct 15% (01:11) wrong based on 67 sessions

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A sequence of consecutive integers begins with 60 and ends with 100. If one integer is randomly selected from the sequence, what is the probability that the integer is even?

(A) 20/41
(B) 1/2
(C) 19/40
(D) 21/41
(E) 21/40

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Re: A sequence of consecutive integers begins with 60 and ends with 100.  [#permalink]

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29 Mar 2018, 23:48
Total number of even numbers will be (100-60)/2 +1=21
Total number of numbers =100-60 +1=41

So probablity=21/41 option D
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Re: A sequence of consecutive integers begins with 60 and ends with 100.  [#permalink]

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30 Mar 2018, 06:49
Bunuel wrote:
A sequence of consecutive integers begins with 60 and ends with 100. If one integer is randomly selected from the sequence, what is the probability that the integer is even?

(A) 20/41
(B) 1/2
(C) 19/40
(D) 21/41
(E) 21/40

Total integers in the sequence = 41 (including 60 and 100)

Total Even Number = 21 (Cause the sequence starts with an even number and ends with an even number)

Probability = Favourable / Total = 21/41

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A sequence of consecutive integers begins with 60 and ends with 100.  [#permalink]

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31 Mar 2018, 12:05
Bunuel wrote:
A sequence of consecutive integers begins with 60 and ends with 100. If one integer is randomly selected from the sequence, what is the probability that the integer is even?

(A) 20/41
(B) 1/2
(C) 19/40
(D) 21/41
(E) 21/40

Possible outcomes = number of terms from 60 to 100: (100-60) = 40. (40+1) = 41

[Mental check: 1,2,3,4. From 1 to 4 there are four terms. (4-1) = 3. ADD 1. (3 + 1) = 4 terms]

Favorable outcomes: even numbers in the range

Number of even terms, increment is 2

# of even terms: $$\frac{(LastTerm-FirstTerm)}{increment} + 1$$

$$\frac{(100-60)}{2}=\frac{40}{2}=20 + 1 = 21$$
even terms

$$\frac{Favorable}{Possible}=\frac{21}{41}$$

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Re: A sequence of consecutive integers begins with 60 and ends with 100.  [#permalink]

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04 Apr 2018, 17:24
Bunuel wrote:
A sequence of consecutive integers begins with 60 and ends with 100. If one integer is randomly selected from the sequence, what is the probability that the integer is even?

(A) 20/41
(B) 1/2
(C) 19/40
(D) 21/41
(E) 21/40

The number of integers from 60 to 100, inclusive, is 100 - 60 + 1 = 41.

The number of even integers from 60 to 100, inclusive, is (100 - 60)/2 + 1 = 21.

So the probability of selecting an even number is 21/41.

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Re: A sequence of consecutive integers begins with 60 and ends with 100. &nbs [#permalink] 04 Apr 2018, 17:24
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