Last visit was: 24 Apr 2024, 13:21 It is currently 24 Apr 2024, 13:21

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 92902
Own Kudos [?]: 618803 [24]
Given Kudos: 81588
Send PM
Most Helpful Reply
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 2873
Own Kudos [?]: 5205 [7]
Given Kudos: 47
Location: India
GPA: 3.12
Send PM
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18756
Own Kudos [?]: 22046 [5]
Given Kudos: 283
Location: United States (CA)
Send PM
General Discussion
Manager
Manager
Joined: 03 Apr 2016
Posts: 75
Own Kudos [?]: 54 [0]
Given Kudos: 102
Location: India
Concentration: General Management, Leadership
GMAT 1: 580 Q43 V27
GMAT 2: 650 Q32 V48
GRE 1: Q160 V151
GPA: 3.99
WE:Design (Consulting)
Send PM
Re: A set of data contains five terms. If the average of those terms is 12 [#permalink]
Bunuel wrote:
A set of data contains five terms. If the average of those terms is 12 and the range of the set is 15, what is the greatest possible value of a term in that set?

A. 12
B. 15
C. 18
D. 21
E. 24


This question expects us to find out the greatest possible value of the term. The question also provides the average of the terms and range of terms. One of the ways of solving such questions is to assign all variables expect one with a lowest possible value 'x' for example. Now, the last variable can be called 'n'.
Since we know mean is 12, we get (x+x+x+x+n)/5 = 12 => 4x+n = 60. Now the range is given as 15 => n-x = 15.
upon solving these two linear equations, we can find out that x=9 and n=60-4*9 = 24. So greatest term in the set is 24, option D
Director
Director
Joined: 02 Oct 2017
Posts: 552
Own Kudos [?]: 481 [3]
Given Kudos: 14
Send PM
Re: A set of data contains five terms. If the average of those terms is 12 [#permalink]
3
Kudos
I go via options..
Largest value in options is 24
So if 24 is largest then for difference of 15, 9 should be minimum.
And remaining 27 out of 60(which is sum) can be easily compensated by 3 9s
So 24 is answer

Posted from my mobile device
Manager
Manager
Joined: 12 Apr 2017
Posts: 109
Own Kudos [?]: 58 [1]
Given Kudos: 33
Location: United States
Concentration: Finance, Operations
GPA: 3.1
Send PM
A set of data contains five terms. If the average of those terms is 12 [#permalink]
1
Kudos
My thought:

5 values, the range is 15 so the lowest plus 15 = maximum value.
Average = 12, so the total of the set is 60

Set each value to the lowest possible = "x"

you get

x + x + x + x + (x+15) = 60
5x + 15 = 60
5x = 45
x = 9
x + 15 = 24
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 32654
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: A set of data contains five terms. If the average of those terms is 12 [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
Re: A set of data contains five terms. If the average of those terms is 12 [#permalink]
Moderators:
Math Expert
92902 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne