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itzmyzone911
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It's given that the average is less than 10 , so
as per condition 2 :

(k+ k+1 + 2k-1 +5k+7 + 6k+8) / 5 < 10
(15k + 15) /5 <10
3k + 3 < 10
3k < 7
and k is integer
so k = 1, 2

For k=1, s={1 , 2, 1, 12, 14} and Median= 2 (condition 1 satisfied)

for k=2, s={2, 3, 3, 17, 20} and Median =3 (condition 1 satisfied)

So K=1 and 2


Yeah but the average being less than 10 is given in statement nr. 2, so how can the answer be "A) Statement 1 alone is sufficient?"

Is there something in the prompt that I'm missing?
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Re-attempting this after some thought:

Placing all values in a number line, it is unclear where k+1 and 2k-1 go, since if k is given different values it is clear that they will shift depending on values for K

itzmyzone911
A set S contains five numbers k, k + 1, 2k - 1, 5k + 7 and 6k + 8. If k is a positive integer, determine its value.

(1) The median of the elements of S is k + 1.


When given this information, we know that this means that k+1 > 2k-1, it is further to the right on the number line

Using this inequality we get that k<2 .... Which means that k MUST be 1 as it is a positive integer.



(2) The average of the elements of S is less than 10.
Given that statement 1 alone is sufficient, this one needs to be either insuff or suff on its own. It is not suff on it's own so that means that the answer is A.

Given OA is A.

My doubt: A is definitely true for k=1. However for k=2, k+1=2k-1, which is also compatible with stmt. 1. This means we have 2 values for k..1 and 2. Then how can A alone be sufficient?
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Re-attempting this after some thought:

Placing all values in a number line, it is unclear where k+1 and 2k-1 go, since if k is given different values it is clear that they will shift depending on values for K

itzmyzone911
A set S contains five numbers k, k + 1, 2k - 1, 5k + 7 and 6k + 8. If k is a positive integer, determine its value.

(1) The median of the elements of S is k + 1.


When given this information, we know that this means that k+1 > 2k-1, it is further to the right on the number line

Using this inequality we get that k<2 .... Which means that k MUST be 1 as it is a positive integer.



(2) The average of the elements of S is less than 10.
Given that statement 1 alone is sufficient, this one needs to be either insuff or suff on its own. It is not suff on it's own so that means that the answer is A.

sabineodf, for statement 1, why don't you consider the equation as \(k+1>=2k-1\)
In this case, you would get \(k<=2\), which means k=1,2.
Thus, insufficient.

Please clarify.
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akhilbajaj

I tested the values.

If k = 2, then as you said 2+1=2*2−1 (3=3). But statement 1) tells us that k+1 is the median, and I think that this statement means that it is the only median, which is wouldn't be if K=2 because then we have a shared median, which leaves that k=1 since it's the only number that fits the parameters, and gives a unique value for the median.

I'm not 100% sure on this.
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akhilbajaj

I tested the values.

If k = 2, then as you said 2+1=2*2−1 (3=3). But statement 1) tells us that k+1 is the median, and I think that this statement means that it is the only median, which is wouldn't be if K=2 because then we have a shared median, which leaves that k=1 since it's the only number that fits the parameters, and gives a unique value for the median.

I'm not 100% sure on this.


In this question, it is said that k+1 is the median, so you should not assume any extra information.
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akhilbajaj

I tested the values.

If k = 2, then as you said 2+1=2*2−1 (3=3). But statement 1) tells us that k+1 is the median, and I think that this statement means that it is the only median, which is wouldn't be if K=2 because then we have a shared median, which leaves that k=1 since it's the only number that fits the parameters, and gives a unique value for the median.

I'm not 100% sure on this.


In this question, it is said that k+1 is the median, so you should not assume any extra information.

K+1 = median

7 values. There must be 3 values on either side of k+1. If k+1 = 2k-1 then they are interchangeable and k+1 is not 100 % the median. But we are given that it IS the median, so that means there must be 2 values either side. I don't think I've made any extreme assumptions/
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Option A :The median of the elements of S is k + 1 .There are 5 elements so two elements on the left and two elements on the right of k+1
so at most k+1>=2k-1 or k+1<=5k+7 .Solving first equation gives us : k<=2 .Second gives k>=6/4 so k=2

Option B : (k +k + 1+2k - 1 +5k + 7 + 6k + 8)/5 < 10 .Solving 3k+3<10 so k<7/3 .k can have values 1,2 So B is not correct .

Hence A is the correct option.

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I think the solution A would be correct if we changed 5k + 7 to 5k - 7:
set S contains five numbers k, k + 1, 2k - 1, 5k - 7 and 6k + 8. If k is a positive integer, determine its value.

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