A small pool filled only with water will require an addition

Question

A small pool filled only with water will require an additional 300 gallons of water in order to be filled to 80% of its capacity. If pumping in these additional 300 gallons of water will increase the amount of water in the pool by 30%, what is the total capacity of the pool in gallons?

A. 1000
B. 1250
C. 1300
D. 1600
E. 1625

A. 1000 
B. 1250 
C. 1300 
D. 1600 
E. 1625

ziko · Accepted Answer

Difficult one in terms of understanding the wording under exam conditions.

we know that 300 gallons will increase the amount of existing water up to 30%, lets say there are x gallons of water and we add 300 => x+300=1.3x => x=1000
Now we now that 1000 gallons already exist in the tank and we add 300 => 1000+300=1300, which is 80% of the total capacity.
So the total capacity is (1300*100)/80=1625 
Answer is E.

Bunuel · Answer

Since pumping in additional 300 gallons of water will increase the amount of water in the pool by 30%, then initially the pool is filled with 1,000 gallons of water.

So, we have that 1,000 + 300 = 0.8*{total} --> {total} = 1,625.

Answer: E.

Hope it's clear.

ShashankDave · Answer

Another way of thinking about this..
we know that adding 300 gallons will increase the water currently in the pool by 30%..
Or...the water will become 130% of itself..and we also know that 30% of the water currently in the pool is 300 gallons..

By unitary method..
if 30% --- 300 gallons
then 130% ---  300 * \frac{130}{100}

This is 80% of the total capacity..so the total capacity will be this value multiplied with

\frac{100}{80}

Thus the total capacity is

300 * \frac{130}{100}*\frac{100}{80}

Which gives us..? (E)

CounterSniper · Answer

let the total capacity and initial water level be x and y respectively

now, as per the question

y+300=.8x -----1

y+300=1.3y ----2
.3y=300
y=1000

substitute in equation 1

1300=.8x
x=13000/8 = 1625

Divyadisha · Answer

300 gallons of water increases capacity by 30% that means

30% is 300 gallons, so 100% would be = 300*100/30= 1000 gallons

Now 1000 +300 gallons is 80% capacity of tank.

so 100% capacity would be= 1300 *100/80= 1625

E is the answer

Archit3110 · Answer

let intial water = a
and total volume = x
given
a+300 = x*80/100

a+300=1.3a
a= 1000 liters
now find value of x
1300*100/80 ; 1625
IMO E

kamrulhasan26043 · Answer

As it said, 300 gallons of water will increase the amount of water in the pool by 30%. 
So, 100 gallons of water will increase the amount of water in the pool by 10%.
So, 100% of the water that we have in the pool is 1000 gallons.

And, They also these 300 gallons will increase the water level by 80%.
So, (1000+300) = 1300 gallons = 80% 
thus, 1625 gallons = 100% 
So, the answer is (E)

ManishaPrepMinds · Answer

Let current water  = x
Additional water = 300 gallons
 This 300 is 30% of x 
So, 300 = 0.3x
x = 1000 (current water)
 Find capacity: 
Current water (1000) + 300 = 1300 = 80% of capacity
1300 = 0.8 × capacity
Capacity = 1300/0.8 = 1625

ANSWER : E

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A small pool filled only with water will require an addition

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