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macjas
Joined: 09 May 2012
Last visit: 30 Jul 2015
Posts: 308
Given Kudos: 100
Affiliations: UWC
Location: Canada
Schools: Rotman '15 (A) Schulich '15 (M)
GMAT 1: 620 Q42 V33
GMAT 2: 680 Q44 V38
GPA: 3.43
WE:Engineering (Media/Entertainment)
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28 May 2012, 02:50
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:31) correct
27%
(01:43)
wrong
based on 277
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A soda can, in the shape of a right circular cylinder, is 3/4 full of soda. If the volume of soda in the can is 72π cubic inches and the diameter of the can is 8 inches, then what is the height, in inches, of the can?
A. 1.5
B. 3
C. 4
D. 4.5
E. 6
A. 1.5
B. 3
C. 4
D. 4.5
E. 6
28 May 2012, 02:56
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macjas
Since the volume of soda in the can is \(72\pi\) and the can is 3/4 full of soda then the volume of the can is \(\frac{3}{4}*can=72\pi\) --> \(can=96\pi\).
The volume of a cylinder is \(\pi{r^2}h\) --> \(\pi{4^2}h=96\pi\) --> \(h=6\).
Answer: E.
19 Jul 2018, 12:33
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macjas
First, let V = the volume of the entire soda can. Since the volume of soda is 72π cubic inches and that represents 3/4 of the volume of the entire soda can, we see that:
(3/4)V = 72π
3V = 288π
V = 96π
Now, using the volume formula of a cylinder, we can solve the height of the can:
V = π r^2 h
96π = π (4)^2 h
96π = 16π h
6 = h
Answer: E
