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Updated on: 20 Feb 2017, 12:30
Originally posted by BrentGMATPrepNow on 20 Feb 2017, 10:46.
Last edited by BrentGMATPrepNow on 20 Feb 2017, 12:30, edited 1 time in total.
Last edited by BrentGMATPrepNow on 20 Feb 2017, 12:30, edited 1 time in total.
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Difficulty:
35%
(medium)
Question Stats:
78% (02:58) correct
22%
(02:59)
wrong
based on 179
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A solid cylinder with radius 3 inches sits in a cylindrical container containing water. The cylindrical container has radius 4 inches, and the water is 6/π inches deep. If the solid cylinder is removed from the container, what will be the depth of the water (in inches)?
A) \(\frac{2}{3π}\)
B) \(\frac{9}{4π}\)
C) \(\frac{7}{3π}\)
D) \(\frac{21}{8π}\)
E) \(\frac{3}{π}\)
* Kudos for all correct solutions
EDIT: I changed the answer choices after I was alerted to a mistake I made.
20 Feb 2017, 11:21
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GMATPrepNow
total volume with cylender inserted - volume of only cylender = volume of water with new height
16π*6/π - 9π*6/π = 16π*H
thus H= 21/8π...........
not getting answer!!!!!!!!!
can anyone explian!!!!!!!!
20 Feb 2017, 11:31
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[quote=[/img]
A solid cylinder with radius 3 inches sits in a cylindrical container containing water. The cylindrical container has radius 4 inches, and the water is 6/π inches deep. If the solid cylinder is removed from the container, what will be the depth of the water (in inches)?
A) \(\frac{2}{3π}\)
B) \(\frac{1}{π}\)
C) \(\frac{3}{2π}\)
D) \(\frac{2}{π}\)
E) \(\frac{3}{π}\)
* Kudos for all correct solutions[/quote]
Same problem
Volume of water: volume of water tank - volume of inserted cylinder = 16π*6/π - 9π*6/π = 96 - 54 = 42
Now for this volume we need to find new height with given radius:
16π*h = 42
h=42/16π = 21/8π
Does not agree with option choices
A solid cylinder with radius 3 inches sits in a cylindrical container containing water. The cylindrical container has radius 4 inches, and the water is 6/π inches deep. If the solid cylinder is removed from the container, what will be the depth of the water (in inches)?
A) \(\frac{2}{3π}\)
B) \(\frac{1}{π}\)
C) \(\frac{3}{2π}\)
D) \(\frac{2}{π}\)
E) \(\frac{3}{π}\)
* Kudos for all correct solutions[/quote]
Same problem
Volume of water: volume of water tank - volume of inserted cylinder = 16π*6/π - 9π*6/π = 96 - 54 = 42
Now for this volume we need to find new height with given radius:
16π*h = 42
h=42/16π = 21/8π
Does not agree with option choices
