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A solution of 140 liters of acid contains 10% of acid and the remainin

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Bunuel
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A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 02:27
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A solution of 140 liters of acid contains 10% of acid and the remaining is water. How many liters of acid needs to be added so that the concentration of acid becomes 1/8th of the solution.

A. 1
B. 2
C. 3
D. 4
E. 5
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LevanKhukhunashvili
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 02:34
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Let x be the pure acid

(140+x)*\(\frac{1}{8}\)=140*0.1+x

x=4

IMO
Ans: D
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RupamPaul13
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 02:36
Let x be the amount of acid required.

(140+x)*1/8=14+x; x=4(Option D)
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 02:51
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Bunuel wrote:
A solution of 140 liters of acid contains 10% of acid and the remaining is water. How many liters of acid needs to be added so that the concentration of acid becomes 1/8th of the solution.

A. 1
B. 2
C. 3
D. 4
E. 5


given info can be written
1/8 * (140+x)= 14+x
solve for x = 4
IMO D
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Lampard42
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 04:21
Acid/solution = 1/8

(Original Acid+Addition)/(Old solution+Addition) = 1/8 ; (14+X)/(140+X) = 1/8 ; 8X+14*8=140+X; 7X = 140-14*8; X=14/7*(10-8) = 4
IMO D
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 06:23
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Bunuel wrote:
A solution of 140 liters of acid contains 10% of acid and the remaining is water. How many liters of acid needs to be added so that the concentration of acid becomes 1/8th of the solution.

A. 1
B. 2
C. 3
D. 4
E. 5


Let the answer be x lt. of acid

(14+x)/(140+x) = 1/8

x= 4
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Diya52
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A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  05 Jun 2019, 06:42
10% of 140litres=14litres of acid. Let x be the litres of acid added to the solution. So the amount of acid in the new solution is (14+x) litres. This is equal to 1/8 of the total new solution which is 140+x. We can set up the equation as 14+x= 1/8(140+x). Or 112+8x=140+x. Or,7x=28. Therefore x=4 litres. Answer D.

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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  06 Jun 2019, 18:14
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Bunuel wrote:
A solution of 140 liters of acid contains 10% of acid and the remaining is water. How many liters of acid needs to be added so that the concentration of acid becomes 1/8th of the solution.

A. 1
B. 2
C. 3
D. 4
E. 5


We can create the equation:

(140 x 0.1 + n)/(140 + n) = 1/8

8(14 + n) = 140 + n

112 + 8n = 140 + n

7n = 28

n = 4

Answer: D
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Re: A solution of 140 liters of acid contains 10% of acid and the remainin [#permalink] New post  08 Mar 2023, 19:10
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