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A sphere, diameter 6, is cut to form a cube. What is the maximum possi

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A sphere, diameter 6, is cut to form a cube. What is the maximum possi  [#permalink]

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New post 28 Sep 2018, 07:25
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A sphere, diameter 6, is cut to form a cube. What is the maximum possible distance between two vertices after the cut?

A. 3
B. \(3\sqrt{2}\)
C. 2π
D. 6
E. 3(π-2)
Manager
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Re: A sphere, diameter 6, is cut to form a cube. What is the maximum possi  [#permalink]

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New post 28 Sep 2018, 08:02
The maximum possible distance between two vertices of a cube with side 'a' is a√3. It goes through the center of the cube.

Now imagine a football and a cube inside the football. The diameter of the football will cut through the center of the cube.

Therefore diameter = max possible distance between two vertices] = 6
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Re: A sphere, diameter 6, is cut to form a cube. What is the maximum possi  [#permalink]

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New post 28 Sep 2018, 08:12
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trankimphuong wrote:
A sphere, diameter 6, is cut to form a cube. What is the maximum possible distance between two vertices after the cut?

A. 3
B. \(3\sqrt{2}\)
C. 2π
D. 6
E. 3(π-2)

Please help to solve this problem, thanks!


OA: D

The maximum Possible distance between two vertices after the cut = Diagonal of cube = Diameter of sphere = 6
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Re: A sphere, diameter 6, is cut to form a cube. What is the maximum possi &nbs [#permalink] 28 Sep 2018, 08:12
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