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# A square ABCD has two of its vertices A and B

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Current Student
Joined: 22 Jun 2016
Posts: 245
A square ABCD has two of its vertices A and B  [#permalink]

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15 May 2017, 07:52
00:00

Difficulty:

45% (medium)

Question Stats:

58% (01:49) correct 42% (02:25) wrong based on 34 sessions

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A square ABCD has two of its vertices A and B at (–1, –1) and (4, 2) respectively. What is the area of the square?

A. 17
B. 21
C. 27
D. 31
E. 34

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Manager
Joined: 27 Mar 2016
Posts: 51
Re: A square ABCD has two of its vertices A and B  [#permalink]

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15 May 2017, 08:53
Side of square =sqrt{((4-(-1))^2+(2-(-1))^2}=√34
Area of square = √34*√34=34.
Hence E.

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Manager
Joined: 03 Oct 2013
Posts: 84
Re: A square ABCD has two of its vertices A and B  [#permalink]

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15 May 2017, 12:04
distance between the two points is sqrt((4-(-1))^2+(2-(-1))^2)

=sqrt(5^2+3^2)

= sqrt(34).

Area = s^2 i.e. 34.

Ans = Option (E)
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Re: A square ABCD has two of its vertices A and B &nbs [#permalink] 15 May 2017, 12:04
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