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14 May 2024, 01:30
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C
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Difficulty:
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Question Stats:
71% (01:17) correct
29%
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A store has several cans of blue paint and several cans of red paint in stock, and has no cans of paint of any other color. If Carla chooses two cans of paint at random from those in stock at this store, what is the probability she picks two cans of red paint?
(1) The number of cans of red paint in the store is equal to the number of cans of blue paint in the store.
(2) The store has a total of 24 cans of paint in stock.
(1) The number of cans of red paint in the store is equal to the number of cans of blue paint in the store.
(2) The store has a total of 24 cans of paint in stock.
14 May 2024, 04:36
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(1) The number of cans of red paint in the store is equal to the number of cans of blue paint in the store.
We cann't reach out to a certain number of cans based on this information. So, we can eliminate A & D answer choice from the question. Now, we are left with BCE.
(2) The store has a total of 24 cans of paint in stock.
This information does not mention specific number of cans with the specific paints, blue & red. Certainly, B is not our answer.
Now, if we combine the above stated information together, we get, 12 numbers of cans with blue paints & 12 numbers of cans with red paints, total 24 numbers of cans.
Probability= number of ways 2 cans can be selected from 12 cans with red paints, 12C2 / number of ways 2 cans can be selected from total 24 number of cans, 24C2. So, the answer is C.
We cann't reach out to a certain number of cans based on this information. So, we can eliminate A & D answer choice from the question. Now, we are left with BCE.
(2) The store has a total of 24 cans of paint in stock.
This information does not mention specific number of cans with the specific paints, blue & red. Certainly, B is not our answer.
Now, if we combine the above stated information together, we get, 12 numbers of cans with blue paints & 12 numbers of cans with red paints, total 24 numbers of cans.
Probability= number of ways 2 cans can be selected from 12 cans with red paints, 12C2 / number of ways 2 cans can be selected from total 24 number of cans, 24C2. So, the answer is C.
19 May 2024, 00:30
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Why wouldn't it be A? If we know that we have the same # of blue and red cans, we know that the probability of choosing either one of them with a random choice will be 0.5. Could anyone please share their reasoning behind this?
