Bunuel
A student conducts an experiment in biology lab and discovers that the ratio of the number of insects in a given population having characteristic X to the number of insects in the population not having characteristic X is 5:3, and that 3/8 of the insects having characteristic X are male insects. What proportion of the total insect population are male insects having the characteristic X ?
(A) 1/1
(B) 5/8
(C) 6/13
(D) 15/64
(E) 1/5
One key to this problem lies in remembering to sum the parts of a ratio.
Insect characteristic ratio:
\(\frac{X}{NotX}=\frac{5}{3}\)Total parts: 5 + 3 = 8
Insects with X therefore = \(\frac{5}{8}\) of the population.
\(\frac{3}{8}\) OF that population with X, that part, are male.
We need one "part," \(\frac{3}{8}\), of another "part," \(\frac{5}{8}\).
To take a fraction of a fraction, multiply.
\(\frac{3}{8} * \frac{5}{8} = \frac{15}{64}\)
The proportion of the total insect population that are male insects having the characteristic X is \(\frac{15}{64}\).
Check: If there are 64 insects total (denominator), \(\frac{5}{8}\) have X.
\(\frac{5}{8}\) * 60 = 40 insects with X (male and female).
Of those 40 with X, \(\frac{3}{8}\) are male.
\(\frac{3}{8}\) * 40 = 15 males with X
Answer D