Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack
GMAT Club

 It is currently 30 Mar 2017, 10:00

Happening Now:

R2 Admission Decisions from Wharton: Join Chat Room 3

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

A student finds the average of 10 positive integers. Each

Author Message
CEO
Joined: 15 Aug 2003
Posts: 3460
Followers: 67

Kudos [?]: 871 [0], given: 781

A student finds the average of 10 positive integers. Each [#permalink]

Show Tags

08 Oct 2003, 18:10
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A student finds the average of 10 positive integers. Each integer contains two digits. By mistake, the boy interchanges the digits of one number say ba for ab. Due to this, the average becomes 1.8 less than the previous one. What was the difference of the two digits a and b?

1) 8
2) 6
3) 2
4) 4
Intern
Joined: 29 Aug 2003
Posts: 47
Location: Detroit, MI
Followers: 0

Kudos [?]: 2 [0], given: 0

Show Tags

08 Oct 2003, 18:27
praetorian123 wrote:
A student finds the average of 10 positive integers. Each integer contains two digits. By mistake, the boy interchanges the digits of one number say ba for ab. Due to this, the average becomes 1.8 less than the previous one. What was the difference of the two digits a and b?

1) 8
2) 6
3) 2
4) 4

Ans: 2 - Option 3

Say, sum of the 9 correct numbers is S

So, (S + (10a + b))/10 - (S + (10b + a))/10 = 1.8
=> 9a - 9b = 18
=> a - b = 2.
Re: PS : Digits   [#permalink] 08 Oct 2003, 18:27
Display posts from previous: Sort by