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14 May 2025, 01:00
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Dropdown 1: negative
Dropdown 2: 12
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:57) correct
30%
(02:05)
wrong
based on 351
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A team of behavioral scientists studied the screen time habits of 13 professionals over a 24-hour period. For each individual, the researchers recorded the number of times they unlocked their work phone during working hours (9:00 a.m. to 5:00 p.m.) and outside of working hours (5:00 p.m. to 9:00 a.m.). The scatterplot shows the results, with each point representing one participant. The horizontal axis shows after-hours phone unlocks; the vertical axis shows unlocks during work hours. A line of best fit is also shown.
The chart indicates correlation between after-hours and work-hours phone usage among participants.
Based on the chart, is the highest total number of phone unlocks (work + after hours) recorded for any single participant during the 24-hour period.
GMAT-Club-Forum-9tvuwwuu.png [ 29.49 KiB | Viewed 1880 times ]
The chart indicates correlation between after-hours and work-hours phone usage among participants.
Based on the chart, is the highest total number of phone unlocks (work + after hours) recorded for any single participant during the 24-hour period.
Attachment:
GMAT-Club-Forum-9tvuwwuu.png [ 29.49 KiB | Viewed 1880 times ]
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Dropdown 1: negative
Dropdown 2: 12
14 May 2025, 08:21
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1) As indicated by the slope, correlation is Negative
2) Highest total number of phone unlocks= 9+3=12 or 7+5= 12
2) Highest total number of phone unlocks= 9+3=12 or 7+5= 12
22 May 2025, 09:00
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Bunuel
Solution:
Dropdown 1: Type of Correlation
From the scatterplot:
- The points show a negative relationship: when nighttime activity increases, daytime activity tends to decrease.
- This is supported by the downward-sloping trendline.
Dropdown 2: Maximum Activity Count
We are asked for the maximum number of times any bird left its nest in the 24-hour period.
Each data point represents:
Total = (daytime departures) + (nighttime departures)
Calculate the maximum of all such totals from the graph. Approximate visually:
A few likely candidates:
- One point at (2, 9): Total = 11
- One at (3, 9): Total = 12
- One at (1, 8): Total = 9
- One at (8, 1): Total = 9
- One at (9, 1): Total = 10
- (3, 9) → 3 (night) + 9 (day) = 12
