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Bunuel
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8% --> correct: cost = (40*5x+50*4x)/(5x+4x)=$400/9, sale= $48, so profit % = ((sale/cost) -1)*100 = ((48*9/400)-1)*100 = (1.08-1)*100=8%
D. 10%
E. 12%
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CP : SP = (5×40+4×50)/(5+4) : 48 = 400/9 : 48 = 400 : 432 =100 : 108

So, Profit% => (108-100) = 8%
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Cost - $40/Kg * 5 + $50/Kg * 4 = $400 / 9 Kg.
Sold =48 * 9 = 432.
Profit % = ( 432 - 400 ) * 100 / 400 = 8%
Option C
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%

Total Cost Price is: 40*5x+50*4x = $400x
Selling Price of the mixture: =48*9x=432x
Profit= 432x-400x=32x
Profit%=\(\frac{32x}{400x}*100= 8%\\
\)

Answer :c
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Hi Bunuel

Can we solve this using scale method. If yes please send the image on how to solve this.
Bunuel
A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%
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