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Bunuel
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 27 Mar 2020, 05:19
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45% (medium)

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70% (02:12) correct 30% (02:30) wrong based on 345 sessions

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A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%
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C
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 27 Mar 2020, 07:29
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Bunuel
A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%


The best way to deal with this question is to find out cost price and selling price by using given ratio as kg.

first type tea is 5 kg and per kg is 40 taka
seceond type is 4 kg and price is 50 taka

cost price :

40 * 5 + 4*50 = 400

Selling price = total kg* selling price per kg = 9 * 48 = 432

profit = 32

profit % = 32/400 = 8%

C is for Covid 19
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 27 Mar 2020, 07:07
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Selling price(SP)=$48
Cost price (CP) =?
Asked profit =SP -CP
Note answers is in % so we rather find the profit% =(SP-CP/CP)•100
Okay let’s go!
(50 - CP)/(CP - 40) = 5/4
9CP = 400 —> CP= $44.44
Profit % = ((48.00-44.44)/44.44)100
Profit % = 8.01 ~ 8%
Or
40——-CP———-50
4x————-5x
9x =10 —> x= 1.1111
So either 40+4(1.1111) =CP or
50-5(1.1111) =CP ,CP= $44.444
Profit % = 8%

C like Covid-19

Bunuel
A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%

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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 27 Mar 2020, 09:39
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8% --> correct: cost = (40*5x+50*4x)/(5x+4x)=$400/9, sale= $48, so profit % = ((sale/cost) -1)*100 = ((48*9/400)-1)*100 = (1.08-1)*100=8%
D. 10%
E. 12%
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 28 May 2020, 23:42
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CP : SP = (5×40+4×50)/(5+4) : 48 = 400/9 : 48 = 400 : 432 =100 : 108

So, Profit% => (108-100) = 8%
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 29 May 2020, 11:21
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Cost - $40/Kg * 5 + $50/Kg * 4 = $400 / 9 Kg.
Sold =48 * 9 = 432.
Profit % = ( 432 - 400 ) * 100 / 400 = 8%
Option C
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 29 May 2020, 23:37
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%

Total Cost Price is: 40*5x+50*4x = $400x
Selling Price of the mixture: =48*9x=432x
Profit= 432x-400x=32x
Profit%=\(\frac{32x}{400x}*100= 8%\\
\)

Answer :c
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A trader mixes two varieties of tea costing $40 per kg and $50 per kg 20 Jun 2025, 22:46
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Hi Bunuel

Can we solve this using scale method. If yes please send the image on how to solve this.
Bunuel
A trader mixes two varieties of tea costing $40 per kg and $50 per kg in the ratio 5:4. If the mixture is then sold at $48 per kg, what is the profit made by the trader?

A. 5%
B. 7.5%
C. 8%
D. 10%
E. 12%
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