Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
01 Dec 2020, 01:15
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
28% (02:47) correct
72%
(02:05)
wrong
based on 88
sessions
History
Date
Time
Result
Not Attempted Yet
A triangle is formed by connecting three points: (0,0), (3,2), and (4m,-1). The line y = mx is then drawn through the triangle, splitting it into two triangles of equal area. What is the sum of all possible values of m?
A. 3/4
B. 1/4
C. 0
D. -1/4
E. -3/4
Are You Up For the Challenge: 700 Level Questions
A. 3/4
B. 1/4
C. 0
D. -1/4
E. -3/4
Are You Up For the Challenge: 700 Level Questions
FauleKatze
GMAT 2: 720 Q48 V40
Posts: 44
Updated on: 01 Dec 2020, 22:35
Originally posted by FauleKatze on 01 Dec 2020, 08:49.
Last edited by FauleKatze on 01 Dec 2020, 22:35, edited 1 time in total.
Last edited by FauleKatze on 01 Dec 2020, 22:35, edited 1 time in total.
Kudos
Bookmarks
Line y=mx coincides with the median of the triangle, as the line divides the triangle into 2 equal parts.
Midpoint of the side of the triangle, which contains points (4m, -1) and (3,2) = [(3+4m)/2,1/2]
Putting the midpoint in the equation y=mx;
1/2=3m+4(m^2)
m^2+(3/4)m-(1/2)=0
using quadratic equation: m= [-(3/4) + X]/2 and [-(3/4) - X]/2
Adding the two possible values of m, we get -3/4.
Answer: E
Midpoint of the side of the triangle, which contains points (4m, -1) and (3,2) = [(3+4m)/2,1/2]
Putting the midpoint in the equation y=mx;
1/2=3m+4(m^2)
m^2+(3/4)m-(1/2)=0
using quadratic equation: m= [-(3/4) + X]/2 and [-(3/4) - X]/2
Adding the two possible values of m, we get -3/4.
Answer: E
01 Dec 2020, 16:13
Kudos
Bookmarks
Bunuel
The large triangle is split into two equal areas, so for the graph below, we must have AC = BC (notice the two smaller triangles share the same height when they use the array AB as their base). Then the expression for point C is the midpoint of A and B, which is \((\frac{4m+3}{2}, \frac{1}{2})\). Finally, this point has to be on the line \(y = mx\), we can plug coordinate C into \(y = mx\) to get:
\(\frac{1}{2} = m*\frac{4m+3}{2}\)
\(1 = 4m^2 + 3m\)
\(4m^2 + 3m - 1 = 0\)
\((4m - 1)(m + 1) = 0\)
\(m = \frac{1}{4}\) or \(m = -1\)
Thus the solutions add up to \(\frac{-3}{4}\).
Ans: E
Attachments
Plot.png [ 21.45 KiB | Viewed 3945 times ]
