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Distance Swimming:Biking: Running = 1:50:12
Average time Swimming:Biking: Running = 3:10:6
LCM of 3,10 & 6 is 30
Therefore,
New average time of Swimming:Biking: Running = 3 ×10 : 10×3 : 6×5
New distance of Swimming:Biking: Running = 10 : 50 × 3 : 12 ×5 = 10: 150 : 60
\(\frac{New distance of Swimming}{Total New distance}\) =\(\frac{10}{220}\)=\(\frac{1}{22}\)
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Distance Ratio: S : B : R = 1:50:12
Time Ratio: S : B : R = 3:10:6

We need to make the time ratio equal by changing the distances

LCM (3,10,6) = 30

New Time Ratio: 30:30:30, i.e. 1:1:1

For that, we need to:

Change in DistanceEffect on Time
1. Increase swim distance 10 times - 10. 1. Time of swim increases 10 times - 30.
2. Increase bike distance 3 times - 150. 2. Time of bike increases 3 times - 30.
3. Increase run distance by 5 times - 60. 3. Time of run increases 5 times - 30.

Time ratio is now equal by these changes.


New Distance Ratio: 30:150:60, i.e. 1:15:6


Swim Ratio: \(\frac{1}{(1+15+6)}\), i.e. \(\frac{1}{22}\) ------ Answer


Sajjad1994
A triathlon consists of three legs: a swim, a bike ride, and a run. A race organizer analyzes the results of a certain triathlon and observes that the ratio of swim distance to bike distance to run distance was 1 to 50 to 12, and that the ratio of average swim time to average bike time to average run time for all participants was 3 to 10 to 6. If the average speed of racers in each leg of the race does not change, but the race organizer changes the distance of each leg of the race so that the average swim time, average bike time, and average run time are now equal to each other, what fraction of the total distance of the race will be represented by the swim leg of the triathlon?

(A) 2/11

(B) 1/22

(C) 3/13

(D) 2/13

(E) 3/22
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