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28 Dec 2024, 00:18
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Difficulty:
65%
(hard)
Question Stats:
69% (02:40) correct
31%
(02:55)
wrong
based on 173
sessions
History
Date
Time
Result
Not Attempted Yet
A truck driver was scheduled to travel a daily route to reach the factory. Generally, he drives at a constant speed of 80 km/h. However, due to road conditions on that day, the driver could only maintain a 60 km/h speed. If the driver has 800 kilometers left to cover in the last 5 hours, for how many hours has the driver already been driving?
(A) 25
(B) 28
(C) 30
(D) 15
(E) 20
(A) 25
(B) 28
(C) 30
(D) 15
(E) 20
*This might be an easy one but this question shows the importance of paying close attention to details. Always keep a note of what is asked.
29 Dec 2024, 02:33
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let the total time be t and the total distance be d.
earlier he used to travel with 80 kpmph, so,
80 = d/t
now,
60=(d-800)/(t-5)
60t - 300 = 80t - 800
20t = 500
t = 25
if total time is 25 hrs, and 5 hrs is still left to cover, then,
the time he has been travelling for is = 20 hrs.
earlier he used to travel with 80 kpmph, so,
80 = d/t
now,
60=(d-800)/(t-5)
60t - 300 = 80t - 800
20t = 500
t = 25
if total time is 25 hrs, and 5 hrs is still left to cover, then,
the time he has been travelling for is = 20 hrs.
HarshaBujji
14 Jan 2025, 07:05
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D S T I--------------X--------I
x=80t 80 t1 (earlier) I<-d=x-800-><-800>
(present) t=t-5 t=5
x-800 60 t-5
x-800=60(t-5) {x=80t}
80t-60t=500
t=25 hr
time required=t-5 = 20 hr
x=80t 80 t1 (earlier) I<-d=x-800-><-800>
(present) t=t-5 t=5
x-800 60 t-5
x-800=60(t-5) {x=80t}
80t-60t=500
t=25 hr
time required=t-5 = 20 hr
