benejo wrote:

A two digit number is randomly selected and multiplied by itself x times. What is the probability that the unit's digit of the resulting number is 1?

(1) x = 12

(2) x is a multiple of 4

Source: ExpertsGlobal

We should know that every 4th power of odd numbers (except 5) always ends in '1'. So basically if N is an odd number ending in 1 or 3 or 7 or 9, then every fourth power of N (N^4 or N^8 or N^12 or N^16...) will end in '1'. 5 is excluded because every positive integral power of 5 ends in 5 only, and all even numbers are also excluded because integral powers of even numbers end in even, cannot end in 1.

So if a two digit number ends in 1 or 3 or 7 or 9 and if it is multiplied by itself 4 times or 8 times or 12 times or 16 times.. it will end in '1'. And in this case the probability will become 4/10; because out of 10 possibilities for last digit (0,1,2,3,4,5,6,7,8,9) - in four cases (1,3,7,9) will fourth power end in '1'.

In each of the two statements, x is a multiple of 4(12 is also a multiple of 4), so in either case - probability of it ending in '1' will be 4/10. So each statement alone is sufficient.

Hence

D answer