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A vessel contains a mixture of milk and water in the ratio of 14 : 3.
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Bunuel
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A vessel contains a mixture of milk and water in the ratio of 14 : 3. [#permalink] New post  08 Mar 2021, 08:15
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A vessel contains a mixture of milk and water in the ratio of 14 : 3. Now, 25.5 litres of the mixture is taken out from the vessel and 2.5 litres of pure water and5 litres of pure milk is added to the mixture. If the resultant mixture contains 20% water, what was the initial quantity of mixture in the vessel before there placement ? (in litres)

(A) 54
(B) 60
(C) 68
(D) 81
(E) 98
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sujoykrdatta
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Re: A vessel contains a mixture of milk and water in the ratio of 14 : 3. [#permalink] New post  08 Mar 2021, 14:15
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Bunuel wrote:
A vessel contains a mixture of milk and water in the ratio of 14 : 3. Now, 25.5 litres of the mixture is taken out from the vessel and 2.5 litres of pure water and5 litres of pure milk is added to the mixture. If the resultant mixture contains 20% water, what was the initial quantity of mixture in the vessel before there placement ? (in litres)

(A) 54
(B) 60
(C) 68
(D) 81
(E) 98


After 25.5 litres were removed, the ratio of milk and water would remain unchanged (removal doesn't change the ratio of the constituents)
So, milk to water remains 14:3 i.e. milk = 14x and water = 3x

Milk and water added = 5 lit and 2.5 lit

Final ratio of milk : water = 80:20 = 4:1

Thus: (14x+5)/(3x+2.5) = 4/1
x = 2.5

Thus, volume in the vessel after removing 25.5 litres = 14x + 3x = 17x
= 17 * 2.5 = 42.5 lit

This, initial volume = 42.5 + 25.5 = 68

Answer C

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Re: A vessel contains a mixture of milk and water in the ratio of 14 : 3. [#permalink]
08 Mar 2021, 14:15
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