Th gap will exist in two situations:
1) Transition from less than 50 to more than 50.
2) Transition from less than 200 but more than 50 to more than 200.
Taking case 1:
51*110 = 5610
Taking an easier value to calculate:
45*120 = 5400>5610.
46 also yields the same.
47 is where the value is higher here and as we move to 51 value becomes lower.
So 47 to 50 =
4 values.
Taking case 2:
We have 200*100 = 20000.
Now from 182*110 to 199*110 we see the values being higher than 20000 satisdfying our condition.
182 to 199,
18 values here.
Total = 4+18 =
22.
Answer:
Option Ekevincan
A wedding planner charges $120 per guest for the first 50 guests. If there are more than 50 but fewer than 200 guests, she charges $110 per guest, and if there are at least 200 guests, she charges $100 per guest. For her wedding, Paula has a list of n confirmed guests and a second list of potential guests. For how many values of n can Paula reduce the wedding planner’s charge by inviting at least one potential guest?
(A) 18
(B) 19
(C) 20
(D) 21
(E) 22