Bunuel wrote:

A worker is paid x dollars for the first 8 hours he works each day. He is paid y dollars per hour for each hour he works in excess of 8 hours. During one week he works 8 hours on Monday, 11 hours on Tuesday, 9 hours on Wednesday, 10 hours on Thursday, and 9 hours on Friday. What is his average daily wage in dollars for the 5-day week?

(A) x + 1.4y

(B) 2x + y

(C) (5x + 8y)/5

(D) 8x + 1.4y

(E) 5x + 7y

Each day he works for 8 hours, he earns \(x\) dollars.

After 8 hours' of work on any one day, he earns \(y\) dollars per hour

M = 8 hrs = $\(x\)

T = 11 = (8 + 3) hrs = $\((x + 3y)\)

W = 9 hrs = (8 + 1)hr = $\((x + 1y)\)

Th = 10 hrs = (8 + 2)hrs = $\((x + 2y)\)

F = 9 hrs = (8 + 1)hrs = $\((x + 1y)\)

Total them:

x + x + 3y + x + 1y + x + 2y + x + 1y = $(5x + 7y)

Divide by 5 days in a work week to get average daily wage in dollars

\(\frac{5x+7y}{5}= x + 1.4y\)

Answer A

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