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05 Nov 2017, 01:48
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
66% (01:46) correct
34%
(01:57)
wrong
based on 231
sessions
History
Date
Time
Result
Not Attempted Yet
A worker is paid x dollars for the first 8 hours he works each day. He is paid y dollars per hour for each hour he works in excess of 8 hours. During one week he works 8 hours on Monday, 11 hours on Tuesday, 9 hours on Wednesday, 10 hours on Thursday, and 9 hours on Friday. What is his average daily wage in dollars for the 5-day week?
(A) x + 1.4y
(B) 2x + y
(C) (5x + 8y)/5
(D) 8x + 1.4y
(E) 5x + 7y
(A) x + 1.4y
(B) 2x + y
(C) (5x + 8y)/5
(D) 8x + 1.4y
(E) 5x + 7y
05 Nov 2017, 09:17
Kudos
Bookmarks
Bunuel
Each day he works for 8 hours, he earns \(x\) dollars.
After 8 hours' of work on any one day, he earns \(y\) dollars per hour
M = 8 hrs = $\(x\)
T = 11 = (8 + 3) hrs = $\((x + 3y)\)
W = 9 hrs = (8 + 1)hr = $\((x + 1y)\)
Th = 10 hrs = (8 + 2)hrs = $\((x + 2y)\)
F = 9 hrs = (8 + 1)hrs = $\((x + 1y)\)
Total them:
x + x + 3y + x + 1y + x + 2y + x + 1y = $(5x + 7y)
Divide by 5 days in a work week to get average daily wage in dollars
\(\frac{5x+7y}{5}= x + 1.4y\)
Answer A
05 Nov 2017, 09:25
Kudos
Bookmarks
Bunuel
Hi..
he earns x dollars every day and it does not vary, so our choice should have ONLY x..
ONLY A and C are left... in C too it is 5x/5 so x...
Now let's work on y
total hour \(8+11+10+9+9=47\)... but he is already paid for \(8*5=40\), so left is \(47-40=7\)
he gets paid y per hour, so 7y average = \(\frac{7y}{5} = 1.4y\)
A is left
ans \(x+1.4y\)
A
