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A young and energetic cobbler fixes 3650 pairs of shoes every year, wh

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A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 14 Jul 2016, 01:51
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A young and energetic cobbler fixes 3650 pairs of shoes every year, while an old yet experienced cobbler fixes 20% less than the young cobbler. In a shoe factory there are two old and one young cobblers working together. How many shoes can the factory fix every day assuming that there are 365 days a year?

A. 26.
B. 34.
C. 36.
D. 44.
E. 48

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Re: A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 14 Jul 2016, 02:01
Bunuel wrote:
A young and energetic cobbler fixes 3650 pairs of shoes every year, while an old yet experienced cobbler fixes 20% less than the young cobbler. In a shoe factory there are two old and one young cobblers working together. How many shoes can the factory fix every day assuming that there are 365 days a year?

A. 26.
B. 34.
C. 36.
D. 44.
E. 48


Ans : A

yc = 3650/365 = 10 s/day

oc = 4/5 * 10 = 8 s/day

2 oc + 1 yc = 26 s/day
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A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 14 Jul 2016, 02:34
young ones do 3650 pairs every year = 10 every day
the old ones do 8 pairs every day

two old and a one young can do 2*8+10 =26 pairs a day = 52 shoes

I guess the question stem should have pair of shoes instead of shoes !!
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Re: A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 14 Jul 2016, 04:42
Bunuel wrote:
A young and energetic cobbler fixes 3650 pairs of shoes every year, while an old yet experienced cobbler fixes 20% less than the young cobbler. In a shoe factory there are two old and one young cobblers working together. How many shoes can the factory fix every day assuming that there are 365 days a year?

A. 26.
B. 34.
C. 36.
D. 44.
E. 48


Number of shoes/day the young cobbler fixes= 3650/365= 10

Number of shoes old cobbler fixes= 3650*80/100

Number of shoes 2 old cobbler fixes in one day= 2* 3650 *80/100 *1/365= 16

Total shoes fixed in one day= 10+16= 26

A is the answer
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Re: A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 15 May 2018, 16:09
Bunuel wrote:
A young and energetic cobbler fixes 3650 pairs of shoes every year, while an old yet experienced cobbler fixes 20% less than the young cobbler. In a shoe factory there are two old and one young cobblers working together. How many shoes can the factory fix every day assuming that there are 365 days a year?

A. 26.
B. 34.
C. 36.
D. 44.
E. 48


The rate of the older cobbler is 0.8 x 3650 = 2,920 pairs of shoes per year.

So the combined daily rate of one young and two old cobblers is:

(2,920 x 2 + 3650)/365 = 9490/365 = 26 pairs of shoes/day.

Alternate Solution:

The daily rate of the young cobbler is 3650/365 = 10 pairs. Thus, the daily rate of an old cobbler is 0.8 x 10 = 8 pairs. So the combined daily rate of one young and two old cobblers is 10 + 2 x 8 = 26 pairs of shoes.

Answer: A
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Re: A young and energetic cobbler fixes 3650 pairs of shoes every year, wh  [#permalink]

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New post 03 Oct 2018, 01:03
Young cobbler fixes shoes in an year= 3650 shoes/yr= 3650/365= 10 shoes/day
Old cobbler fixed 20% less shoes than young cobbler per day= 10-(10*20/100)= 8 shoes/day
So, 2 old & 1 young cobbler fixes shoes per day= (8*2)+10= 26 shoes

(A)
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Re: A young and energetic cobbler fixes 3650 pairs of shoes every year, wh &nbs [#permalink] 03 Oct 2018, 01:03
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