'abc' is a 3 digit natural number such that 'abc' = a^3 + b^3 + c^3

a is clearly 3..
So 3bc=\(3^3+b^3+c^3\)...
Now, 5< max(b,c) <8 must be true, because if max(b,c) is 8 or 9, a^3 + b^3 + c^3 will exceed 400. If max(b,c) is less than 6, a^3 + b^3 + c^3 will be smaller than 300

Case 1. When b or c equals to 6
Let b=6,
300 < a^3 + b^3 + c^3 < 400
300< 27+216+c^3< 400
57< c^3< 157
c can take only 4 or 5
When c is 4, a^3 + b^3 + c^3= 307 not equal to abc
When c is 5, a^3 + b^3 + c^3= 368 not equal to abc
Similarly When c=6, b can take 4 or 5...in both cases a^3 + b^3 + c^3 is not equal to abc

Case 2. When b or c equals to 7
Let b=7
300 < a^3 + b^3 + c^3 < 400
300< 27+343+c^3<400
or c^3< 30
c can take 0,1,2 or3
only c=0 or 1 satisfies a^3 + b^3 + c^3=abc

When c=7, b can take 0,1,2 or 3. None will satisfies our condition.

Hence 370 and 371 are only two 3-digits number between interval 300 and 400, when a^3 + b^3 + c^3=abc

Statement 1. When abc is even
abc=370
Sufficient

Statement2 When abc is multiple of 5
abc=370
Sufficient

Answer is D