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31 Aug 2019, 17:35
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
73% (02:12) correct
27%
(03:03)
wrong
based on 26
sessions
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Time
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Not Attempted Yet
ABCD is a parallelogram. DE is perpendicular to AB, and DF is perpendicular to BC. Length of AB=20, BC =15 and DE=9 units.
Find the length of DF?
A. 6
B. 8
C. 10
D. 12
E. 15
Find the length of DF?
A. 6
B. 8
C. 10
D. 12
E. 15
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69830226_2446154635461942_8119332418332131328_n.jpg [ 13.1 KiB | Viewed 3123 times ]
31 Aug 2019, 22:48
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If we draw a line from D to B, we will have two triangles with the same areas.
The area of ADB=20*9 /2 =90
So, 90= h *15 /2
h=90*2/15=12
Option D
Posted from my mobile device
The area of ADB=20*9 /2 =90
So, 90= h *15 /2
h=90*2/15=12
Option D
Posted from my mobile device
31 Aug 2019, 22:53
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nick1816
Given:
1. ABCD is a parallelogram.
2. DE is perpendicular to AB, and DF is perpendicular to BC.
3. Length of AB=20, BC =15 and DE=9 units.
Asked: Find the length of DF.
sin DAE = sin FCD
9/15=h/20
h= 12
IMO D
Posted from my mobile device
