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04 Feb 2025, 23:32
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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ABCD is a quadrilateral, with AD parallel to BC (see figure). E is a point between A and D such that BE represents the height of ABCD and E is the midpoint of AD. If the area of triangle ABE is 12.5 square inches, what is the area of ABCD?
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08 Feb 2025, 00:14
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OE
Therefore, the length AD is 2x = 10.
Because AD is parallel to BC, the shape ABCD is a trapezoid.
GMAT-Club-Forum-lpy89had.jpeg [ 6.37 KiB | Viewed 164 times ]
GMAT-Club-Forum-4i8gbb8o.jpeg [ 6.25 KiB | Viewed 165 times ]
If E is the midpoint of AD, then AE = ED. Set x as the length of each of AE and ED. Use the area of the triangle to determine the length of x:
Therefore, the length AD is 2x = 10.
Because AD is parallel to BC, the shape ABCD is a trapezoid.
Attachment:
GMAT-Club-Forum-lpy89had.jpeg [ 6.37 KiB | Viewed 164 times ]
Attachment:
GMAT-Club-Forum-4i8gbb8o.jpeg [ 6.25 KiB | Viewed 165 times ]
