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19 Jul 2019, 06:12
Kudos
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B
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Difficulty:
55%
(hard)
Question Stats:
50% (01:36) correct
50%
(00:59)
wrong
based on 6
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ABCD is a square of area 4 with diagonals AC and BD, dividing square into 4 congruent triangles. Figure looks like four non-over lapping triangles. Then the sum of the perimeters of the triangles is
a. 8(2 + √2)
b. 8(1+ √2)
c. 4(1 + √2)
d. 4(2 + √2)
a. 8(2 + √2)
b. 8(1+ √2)
c. 4(1 + √2)
d. 4(2 + √2)
20 Jul 2019, 20:28
Kudos
Bookmarks
cfc198
ABCD is a square of area 4 with diagonals AC and BD, dividing square into 4 congruent triangles. Figure looks like four non-over lapping triangles. Then the sum of the perimeters of the triangles is
a. 8(2 + √2)
b. 8(1+ √2)
c. 4(1 + √2)
d. 4(2 + √2)
a. 8(2 + √2)
b. 8(1+ √2)
c. 4(1 + √2)
d. 4(2 + √2)
Area of square = 4
--> Side = 2
Perimeter of all triangles so formed = Sum of all sides + 2*Sum of diagonal lengths
= 4*2 + 2*(2√2 + 2√2)
= 8 + 8√2
= 8(1 + √2)
Option B
