It is currently 12 Dec 2017, 01:40

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Absolutes QUESTION - MGMAT Article

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Intern
Intern
avatar
B
Joined: 31 Aug 2016
Posts: 13

Kudos [?]: [0], given: 0

Absolutes QUESTION - MGMAT Article [#permalink]

Show Tags

New post 30 Nov 2017, 07:49
Hello guys,

this article: https://www.manhattanprep.com/gmat/tuto ... -value.cfm talks about the critical points in absolutes.
It has this example: |x + 1| + |x - 3| = 6 where the critical points are -1 and 3 and defines the critical points as the numbers that zero | |.

Why in the inequality below the critical point is not -3? It is -6 and 0.
|x+3|>3 is equal to x e (-inf,-6)&(0,+inf)

Thanks

Kudos [?]: [0], given: 0

Expert Post
Math Expert
User avatar
D
Joined: 02 Aug 2009
Posts: 5339

Kudos [?]: 6099 [0], given: 121

Re: Absolutes QUESTION - MGMAT Article [#permalink]

Show Tags

New post 30 Nov 2017, 08:09
standyonda wrote:
Hello guys,

this article: https://www.manhattanprep.com/gmat/tuto ... -value.cfm talks about the critical points in absolutes.
It has this example: |x + 1| + |x - 3| = 6 where the critical points are -1 and 3 and defines the critical points as the numbers that zero | |.

Why in the inequality below the critical point is not -3? It is -6 and 0.
|x+3|>3 is equal to x e (-inf,-6)&(0,+inf)

Thanks



hi.

the critical point is -3 itself..
at x<-3, x+3 will be NEGATIVE, so -(x+3)>3.....x+3<-3....x<-6...lower limit -Inf
at x>=-3, x+3>3...x>0.. Higher limit +inf
_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

Kudos [?]: 6099 [0], given: 121

Intern
Intern
avatar
B
Joined: 31 Aug 2016
Posts: 13

Kudos [?]: [0], given: 0

Re: Absolutes QUESTION - MGMAT Article [#permalink]

Show Tags

New post 30 Nov 2017, 08:14
chetan2u wrote:
standyonda wrote:
Hello guys,

this article: https://www.manhattanprep.com/gmat/tuto ... -value.cfm talks about the critical points in absolutes.
It has this example: |x + 1| + |x - 3| = 6 where the critical points are -1 and 3 and defines the critical points as the numbers that zero | |.

Why in the inequality below the critical point is not -3? It is -6 and 0.
|x+3|>3 is equal to x e (-inf,-6)&(0,+inf)

Thanks



hi.

the critical point is -3 itself..
at x<-3, x+3 will be NEGATIVE, so -(x+3)>3.....x+3<-3....x<-6...lower limit -Inf
at x>=-3, x+3>3...x>0.. Higher limit +inf


Thanks!! So to find the range you use the critical point that in the end it has nothing to do with the range. The CP is a step.

Kudos [?]: [0], given: 0

Re: Absolutes QUESTION - MGMAT Article   [#permalink] 30 Nov 2017, 08:14
Display posts from previous: Sort by

Absolutes QUESTION - MGMAT Article

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.