DisciplinedPrep
Adam and John simultaneously leave points x and y towards y and x respectively and travel in the same route. After meeting each other on the way, Adam takes 4 hours to reach his destination, while John takes 9 hours to reach his destination. If the speed of Adam is 48 mph, what is the speed of John?
A. 72 mph
B. 60 mph
C. 32 mph
D. 80 mph
E. 120 mph Solution:
We can let n be the number of hours it takes for Adam and John to meet and r be the speed of John. Then the distance between x and y can be expressed as any one of the following:
48(n + 4) (using Adam’s rate and time)
r(n + 9) (using John’s rate and time)
and
(48 + r) * n (using both Adam’s and John’s rates and time when they meet)
Since they represent the same distance, we can set the second and third expressions equal to each other:
r(n + 9) = (48 + r) * n
rn + 9r = 48n + rn
9r = 48n
n = 9r/48 = 3r/16
Now setting the first and second expressions equal to each other and substituting 3r/16 for n, we have:
48(n + 4) = r(n + 9)
48n + 192 = rn + 9r
48(3r/16) + 192 = r(3r/16) + 9r
9r + 192 = 3r^2/16 + 9r
192 * 16 = 3r^2
64 * 16 = r^2
r = 8 x 4 = 32
Alternate Solution:Notice that if two bodies travel towards each other, the faster body will always reach its destination sooner than the slower body. Since the two bodies will have traveled for an equal time at the moment they meet, the faster body will spend less time after they meet.
Using the above observation, we can determine that Adam travels faster than John since Adam only takes 4 hours to reach point y while John takes 9 hours to reach point x after they meet. The only answer choice less than Adam’s speed of 48 mph is C: 32 mph.
Answer: C