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DisciplinedPrep
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Adam, Bart, and Carol started working together to complete a task in 08 May 2019, 08:54
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A
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95% (hard)

Question Stats:

32% (01:50) correct 68% (01:55) wrong based on 25 sessions

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Adam, Bart, and Carol started working together to complete a task in a certain number of days. In the course of work, they remained absent for a few days and therefore the work was completed 3 days later than planned. If Adam and Bart remained absent for 2 and 4 days more than Carol, then Carol remained absent for how many days?

A. 1 day
B. 2 days
C. 3 days
C. 4 days
E. 5 days

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Adam, Bart, and Carol started working together to complete a task in 08 May 2019, 19:34
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DisciplinedPrep
Adam, Bart, and Carol started working together to complete a task in a certain number of days. In the course of work, they remained absent for a few days and therefore the work was completed 3 days later than planned. If Adam and Bart remained absent for 2 and 4 days more than Carol, then Carol remained absent for how many days?

A. 1 day
B. 2 days
C. 3 days
C. 4 days
E. 5 days
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Hello ,
Can you explain how we can do this without knowing the actual number of days planned ?

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RitikA
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Adam, Bart, and Carol started working together to complete a task in 09 May 2019, 11:03
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DisciplinedPrep
Adam, Bart, and Carol started working together to complete a task in a certain number of days. In the course of work, they remained absent for a few days and therefore the work was completed 3 days later than planned. If Adam and Bart remained absent for 2 and 4 days more than Carol, then Carol remained absent for how many days?

A. 1 day
B. 2 days
C. 3 days
C. 4 days
E. 5 days
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VeritasKarishma :

Please help with this question. I am not able to find any clue how to start.

Isn't this question too hard to be tested on the GMAT along with this question : https://gmatclub.com/forum/adam-and-bry ... fl=similar

Your views on difficult of these questions are required.
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Adam, Bart, and Carol started working together to complete a task in 11 May 2019, 08:04
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Interesting question!

Let's say the work was scheduled to be completed in 'x' days (assuming, of course, that all three of them would be working for 'x' days without abstentions).
So, 3x man-days are required to complete the work.
Due to abstentions, completion of work was delayed by 3 days. That is, the work was finished (x+3) days after they started. Of these (x+3) days, let's say Carol was absent for 'y' days.
So Carol worked for [(x+3) - y] days
Then, Adam worked for [(x+3) - (y+2)] days
And Bart worked for [(x+3) - (y+4)] days
So, the three of them worked for (3x+9-3y-6) man-days in total to finish the work. But 3x man-days are needed to complete the work.
Therefore, 3x-3y+3=3x----> y=1. Ans: A
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Adam, Bart, and Carol started working together to complete a task in 11 May 2019, 08:24
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effatara
Interesting question!

Let's say the work was scheduled to be completed in 'x' days (assuming, of course, that all three of them would be working for 'x' days without abstentions).
So, 3x man-days are required to complete the work.
Due to abstentions, completion of work was delayed by 3 days. That is, the work was finished (x+3) days after they started. Of these (x+3) days, let's say Carol was absent for 'y' days.
So Carol worked for [(x+3) - y] days
Then, Adam worked for [(x+3) - (y+2)] days
And Bart worked for [(x+3) - (y+4)] days
So, the three of them worked for (3x+9-3y-6) man-days in total to finish the work. But 3x man-days are needed to complete the work.
Therefore, 3x-3y+3=3x----> y=1. Ans: A
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Thanks

Have you assumed that all three have same rate to say that you need 3x mandays?
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Adam, Bart, and Carol started working together to complete a task in 11 May 2019, 11:46
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Mo2men

Yes, I did. Since nothing to the contrary is mentioned that is an automatic assumption.

There is actually a quicker way of solving this:
3 extra days means 3*3=9 man-days have been lost due to abstentions. Let's say Carol absented for 'y' days. Then, Adam and Bart absented for (y+2) and (y+4) days respectively. Consequently, [y+(y+2)+(y+4)]=(3y+6) man-days were lost.
So, 3y+6=9---> y=1

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