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After her birthday, Fiona had D dollars in gift money.
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15 Jul 2018, 05:43
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78% (01:51) correct 22% (02:47) wrong based on 126 sessions
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After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D? A. $240 B. $300 C. $320 D. $360 E. $480
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Re: After her birthday, Fiona had D dollars in gift money.
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15 Jul 2018, 06:52
adkikani wrote: After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D?
A. $240 B. $300 C. $320 D. $360 E. $480 OA: B Initial amount =\(D\) Amount remaining after buying Electric Skateboard =\(D \frac{3D}{5}\) Amount remaining after buying movie ticket =\(D \frac{3D}{5} \frac{1}{3}\)\((D \frac{3D}{5})=D*\frac{2}{5}*\frac{2}{3}\) As per question stem,\(D*\frac{2}{5}*\frac{2}{3}=80\) \(D=300\)



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Re: After her birthday, Fiona had D dollars in gift money.
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15 Jul 2018, 06:59
BismarckCan you please comment on text in RED? Initial amount =\(D\) Amount remaining after buying Electric Skateboard =\(D \frac{3D}{5}\) OK, I simplified this to get \(\frac{2D}{5}\)Amount remaining after buying movie ticket =\(D \frac{3D}{5} \frac{1}{3}\)\((D \frac{3D}{5})=D*\frac{2}{5}*\frac{2}{3}\) I directly multiplied 1/3 *(2D/5) and then took 1(2D/15) to equate to 80 Where did I go wrong?
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Re: After her birthday, Fiona had D dollars in gift money.
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15 Jul 2018, 07:23
Can you please comment on text in RED?
Initial amount =\(D\)
Purchase 1 Amount remaining after buying Electric Skateboard =\(D \frac{3D}{5}\) OK, I simplified this to get \(\frac{2D}{5}\) After buying Electric Skateboard,She has now \(\frac{2D}{5}\) remaining with her, instead of \(D\)
Purchase 2 Amount remaining after buying movie ticket =\(D \frac{3D}{5} \frac{1}{3}\)\((D \frac{3D}{5})=D*\frac{2}{5}*\frac{2}{3}\) I directly multiplied 1/3 *(2D/5) and then took 1(2D/15) to equate to 80 Where did I go wrong?
Movie ticket price =\(\frac{1}{3} *(\frac{2D}{5})\) Money remaining after Purchase 2 = Money remaining after Purchase 1  Movie ticket price =\(\frac{2D}{5}\)  \(\frac{1}{3} *(\frac{2D}{5})\) Money remaining after Purchase 2\(=\)\(\frac{2D}{5}\) \(\) \(\frac{1}{3} *(\frac{2D}{5})\)\(=80\)



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After her birthday, Fiona had D dollars in gift money.
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21 Jul 2018, 04:52
adkikani wrote: After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D?
A. $240 B. $300 C. $320 D. $360 E. $480 Answer choices seem easy : Start with B as it seems easiest to work with: Say D = $ 300 Expense on skate boards = 3/5 * 300 = $ 180 Balance amount = 300  180 = $ 120 Expense on smart card = 1/3 * 120 = $ 40 Total expense = 180 + 40 = $ 220 Amount left to put in the bank = 300  220 = $ 80 (perfect match) (B)
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Re: After her birthday, Fiona had D dollars in gift money.
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13 Aug 2018, 08:02
can somebody explain to me why this approach is incorrect:
I assume that Fiona has in total x dollars.
After the first purchase she is left with 5/3 of x and from this remaining amount she makes a second purchase which is 1/3 of the this amount.
Hence I calculated:
3/5x+1/3(3/5x)+80 = x > 9/15x + 3/15x+80 = x > 12/15x+80=x > 4/5x+80=x >80 = 1/5x > x = 400
Where is my logical flaw? From the post above it doesn't come clear to me.
Thanks in advance.
Max



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Re: After her birthday, Fiona had D dollars in gift money.
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06 Jan 2019, 09:01
adkikani wrote: After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D?
A. $240 B. $300 C. $320 D. $360 E. $480 One option is to WORK BACKWARDS The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank.If she spent 1/3 of her money on a movie passcard, then 2/3 of her money remained (which she put in the bank). This means 2/3 of her money = $80 We can also say that 1/3 of her money = $40 So, she spent $40 on a movie passcard and saved $80 In other words, at the beginning of that day, she had $120After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard.If she spent 3/5 of her money (on a skateboard), then 2/5 of her money remained (to be spent on a movie passcard the following day). In other words, 2/5 of D = $120Or we can write: (2/5)D = $120Multiply both sides by 5 to get: 2D = $600 Divide both sides by 2 to get: D = $300 Answer: B Cheers, Brent
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Re: After her birthday, Fiona had D dollars in gift money.
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06 Jan 2019, 09:15
adkikani wrote: After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D?
A. $240 B. $300 C. $320 D. $360 E. $480 Another approach is to use algebra. After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard.If Fiona SPENT 3/5 of D dollars, then 2/5 of D dollars REMAINED In other words, the amount remaining at the end of the day = 2D/5 dollars The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank.If Fiona SPENT 1/3 of her remaining 2D/5 dollars, then she must have SAVED 2/3 of 2D/5 dollars 2/3 of 2D/5 = (2/3)( 4D/5) = 4D/15So, after spending 1/3 of her money that day, 4D/15 dollars remained (which she put in the bank) In other words, 4D/15 = $80What was the value of D?Take: 4D/15 = $80Multiply both sides by 15 to get: 4D = 1200 Divide both sides by 4 to get: D = $300 Answer: B Cheers, Brent
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Re: After her birthday, Fiona had D dollars in gift money.
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06 Jan 2019, 13:00
Hi All, We're told that after her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard, then she spent 1/3 of what WAS LEFT on a movie passcard, and then finally put the last $80 in the bank. Assuming she made no other purchases with that money, we're asked for the value of D. This question can be solved in a number of different ways, including by TESTing THE ANSWERS. Based on the given Answers, it looks like Answer B would be the easiest to work with, so let's start there... Answer B: $300 IF.... D = $300.... Fiona spent (3/5)($300) = $180 on a skateboard, leaving her with $300  $180 = $120 She then spent (1/3)($120) = $40 on a movie passcard, leaving her with $120  $40 = $80 This is an exact match for what we were told, so this must be the answer! Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: After her birthday, Fiona had D dollars in gift money.
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22 Jun 2019, 21:31
adkikani wrote: After her birthday, Fiona had D dollars in gift money. She spent 3/5 of this on an electric skateboard. The next day, she spent 1/3 of what was left on a movie passcard, and then finally put the last $80 in the bank. If she made no other purchases with that money, then what was the value of D?
A. $240 B. $300 C. $320 D. $360 E. $480 She spent 3/5 of this on an electric skateboard. —> Spent = 3D/5 —> Remaining = 2D/5 she spent 1/3 of what was left —> Remaining = 2/3*2D/5 = 4D/15 Given, 4D/15 = 80 —> D = 80*15/4 = 300 $ IMO Option B Posted from my mobile device




Re: After her birthday, Fiona had D dollars in gift money.
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