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25 Apr 2019, 23:39
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After the first two terms in a sequence of numbers, each term in the sequence is formed by adding all of the preceding terms. Is 12 the fifth term in the sequence?
1. The sum of the first 3 terms in the sequence is 6.
2. The fourth term in the sequence is 6.
NEW question from GMAT® Official Guide 2020
ID: DS92602
1. The sum of the first 3 terms in the sequence is 6.
2. The fourth term in the sequence is 6.
NEW question from GMAT® Official Guide 2020
ID: DS92602
Archived Topic
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25 Apr 2019, 23:54
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Let the first term be a and second term be b...
Sequence will be - a,b,a+b,2a+2b,4a+4b....
Is 4a+4b = 12.. is 4(a+b) = 12
Is a+b = 3...
Statement 1 - the sum of first three terms is 6..
a+b+(a+b) = 6... 2a+2b= 6 , a+b = 3... Statement 1 is sufficient..
Statement 2 - the fourth term is 6..
2a+2b = 6... A+b = 3... Statement 2 is sufficient...
Option D is the right one...
Posted from my mobile device
Sequence will be - a,b,a+b,2a+2b,4a+4b....
Is 4a+4b = 12.. is 4(a+b) = 12
Is a+b = 3...
Statement 1 - the sum of first three terms is 6..
a+b+(a+b) = 6... 2a+2b= 6 , a+b = 3... Statement 1 is sufficient..
Statement 2 - the fourth term is 6..
2a+2b = 6... A+b = 3... Statement 2 is sufficient...
Option D is the right one...
Posted from my mobile device
26 Apr 2019, 00:21
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After the first two terms in a sequence of numbers, each term in the sequence is formed by adding all of the preceding terms. Is 12 the fifth term in the sequence?
Now, we are just looking at fifth term, so we can write the first five terms, when first two terms are x and y
So, x, y, ... Third term=(x+y)... fourth term=(x+y)+x+y=2(x+y), and fifth term = 4(x+y)..
The general term is \(2^{n-3}(x+y)\), so fifth term = \(2^{5-3}(x+y)=4(x+y)\)
1. The sum of the first 3 terms in the sequence is 6.
so sum of the first 3 terms in the sequence=4th term = \(2^{4-3}(x+y)=2(x+y)=6.......x+y=3\)
So, 4(x+y)=483=12
suff
2. The fourth term in the sequence is 6.
Same as statement I
Suff
D
Now, we are just looking at fifth term, so we can write the first five terms, when first two terms are x and y
So, x, y, ... Third term=(x+y)... fourth term=(x+y)+x+y=2(x+y), and fifth term = 4(x+y)..
The general term is \(2^{n-3}(x+y)\), so fifth term = \(2^{5-3}(x+y)=4(x+y)\)
1. The sum of the first 3 terms in the sequence is 6.
so sum of the first 3 terms in the sequence=4th term = \(2^{4-3}(x+y)=2(x+y)=6.......x+y=3\)
So, 4(x+y)=483=12
suff
2. The fourth term in the sequence is 6.
Same as statement I
Suff
D
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
