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23 Oct 2009, 18:11
Kudos
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what is y?
1) cube(y)+2y = y +2*sqr(y)
2) sqr(y) = y
Taking statement 1, dividing both sides by y, we get sqr(y) - 2y +1 = 0 => (y-1)^2 = 0=> y-1 = 0 and hence y =1
Taking statement 2, dividing both sides by y, we straight away get y =1, but the OA is given as niether statement is sufficients...could some one please explain
1) cube(y)+2y = y +2*sqr(y)
2) sqr(y) = y
Taking statement 1, dividing both sides by y, we get sqr(y) - 2y +1 = 0 => (y-1)^2 = 0=> y-1 = 0 and hence y =1
Taking statement 2, dividing both sides by y, we straight away get y =1, but the OA is given as niether statement is sufficients...could some one please explain
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23 Oct 2009, 19:17
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ISBtarget
Hey, never divide both sides for any thing that you are not sure whether or not it could be Zero. In both statements, y=1 or 0
24 Oct 2009, 12:25
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DavidArchuleta
thanks for the info
Even otherwise, take statement 1
take y out of left and right handside y ( y^2+2) = y ( 2y+1)
cancel out y on both sides , we get y^2 -2y+1 which is (y-1)^2 = 0 , which is y =1.
could you please explain
