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say total = 100x
programmers =p
analyst = 100x-p

on monday, programmer is absent.
so present programmers = p-1
and present analyst = 100x-p

this present programmers are 1/7 of total present employees.
so total present employees = p-1+100x-p = 100x-1
so, p - 1 = (1/7) * 100x-1
we get, 100x= 7p-6

now on tuesday , two analyst are absent.
so present analyst= 100x-p-2
present programmers= p

total present all employees= 100x-p-2+p = 100x-2
now the programmers are 1/5 of all present employees.

so, p = (1/5)* (100x-2)
now we know 100x= 7p-6. so from that we can find value of p and then of x.
p= (1/5) *(7p-6-2)
5p = 7p-8
p= 4
so from that we get x=22/100

now total employee= 22
programmers= 4
analyst= 18

on wednesday, 2 of each programmers and anlayst are absent.
so present programmers= 2
present analyst= 16

total present employee= 18

we need programmers proportion on wednesday.
thats 2/18 = 1/9

ans D
kevincan
All employees of Celtic Systems are either programmers or systems analysts. On Monday, one programmer was absent, and programmers made up \(\frac{1}{7}\) of the employees present. On Tuesday, two systems analysts were absent, and programmers made up \(\frac{1}{5}\) of the employees present. On Wednesday, two programmers and two systems analysts were absent.

What fraction of the employees present on Wednesday were programmers?

(A) \(\frac{2}{25}\)
(B) \(\frac{1}{10}\)
(C) \(\frac{2}{19}\)
(D) \(\frac{1}{9}\)
(E) \(\frac{1}{8}\)
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