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20 Feb 2020, 13:26
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A
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Difficulty:
25%
(medium)
Question Stats:
81% (02:10) correct
19%
(02:40)
wrong
based on 124
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Amal can complete a job in 10 days and Bimal can complete it in 8 days. Amal, Bimal and Kamal together complete the job in 4 days and are paid a total amount of Rs 1000 as remuneration. If this amount is shared by them in proportion to their work, then Kamal's share, in rupees, is
A. 100
B. 200
C. 300
D. 400
E. 500
A. 100
B. 200
C. 300
D. 400
E. 500
20 Feb 2020, 14:59
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1/10+1/8+1/x=1/4
1/x=1/40
1/10+1/8=9/40
1/x=1/40
1/10 of 1000
100
Posted from my mobile device
1/x=1/40
1/10+1/8=9/40
1/x=1/40
1/10 of 1000
100
Posted from my mobile device
21 Feb 2020, 00:16
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cantaffordname
Solution
- • Let the complete job consists of 80 units of work.
• Amal can complete the job in 10 days.
- o So, in 1-day Amal will do (\(\frac{80}{10} = 8 \)) units of work
- o So, in 1-day Bimal will do (\(\frac{80}{8} = 10\)) units of work.
• Now, Amal, Bimal and Kamal can together complete the work in 4 days.
- o This means, Amal, Bimal and Kamal will together do (\(\frac{80}{4} = 20\)) units of work in 1 day.
- Thus, Units of work that Kamal does in 1 day \(= 20-18 =2\) units.
- o Remuneration received by Kamal = ratio of work completed by Kamal to the total work * 1000 = \(\frac{2}{20}*1000\) = 100
