I think E,
Given - Amy and Maria leave
separately on their bikes
from the same point of a shopping mall to go to a restaurant for dinner.
To find - If Amy leaves first, how many minutes will Maria bike before she is 0.2 miles ahead of Amy lets check statements.
1st - Amy leaves 10 minutes ahead of Maria.
Assuming amy traveling at speed a mph, So Maria needs to cover the lead of 10 min that has been given to amy first before she takes 0.2 miles lead.
Distance covered by amy in 10 minutes before maria starts = a * 10 / 60 = a/6.
Nothing else is given. Not sufficient.
2nd - Maria bikes 2 miles per hour faster than Amy.
Maria speed = a + 2 mph.
Relative speed = Maria speed - Amy speed = 2 mph
From here we can only calculate time taken by maria to take lead of 0.2 miles after maria crosses amy
t' = Lead distance / Relative speed = 0.2 / 2 = 0.1 hr
but we need total time for maria that we can't calculate unless we know the earlier lead of 10 min which was given to amy and we dont have anything else to calculate that. Hence Not sufficient.
Now after combining both, t = time taken by maria to cover the lead of first 10 min of amy
= Distance covered by amy in 10 min / Relative speed
= (a/6) / 2 = a/12
but we dont know amy speed hence we cant conclude anything.