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B
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Difficulty:
65%
(hard)
Question Stats:
54% (01:49) correct
46%
(01:52)
wrong
based on 347
sessions
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Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?
A. 10
B. 8
C. 6
D. 4
E. 2
Source: Other - https://www.majortests.com/gmat/problem_solving_test01
Attachment:
1.gif [ 1.68 KiB | Viewed 56634 times ]
18 Jun 2014, 21:27
Kudos
Bookmarks
kumar83
From A, there are two things Amy can do - go to B or to C. Since the paths are not symmetrical along B and C, you will need to consider them separately.
Case 1: Go to B first
A to B - 1 way
B to C - 2 ways
C to A - 2 ways
Total number of ways in this case = 1*2*2 = 4
Case 2: Go to C first
A to C - 2 ways
C to B - 2 ways
B to A - 1 way
Total number of ways in this case = 2*2*1 = 4
Total number of ways = 4+4 = 8
19 Jun 2014, 02:03
Kudos
Bookmarks
Refer diagram below:
Possible combinations via route A - B - C - A = 4
a - b1 - c1
a - b1 - c2
a - b2 - c1
a - b2 - c2
Possible combinations via route A - C - B - A = 4
Total = 8
Answer = B
Possible combinations via route A - B - C - A = 4
a - b1 - c1
a - b1 - c2
a - b2 - c1
a - b2 - c2
Possible combinations via route A - C - B - A = 4
Total = 8
Answer = B
Attachments
1.gif [ 2.18 KiB | Viewed 50431 times ]
