Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 1612:00 PM EDT
-11:59 PM EDT
You’re first to know: Save $200 on GMAT prep starting tomorrow, 4/13. Get 6 official practice tests and study with real questions. Be ready to save!
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
26 May 2025, 21:44
Kudos
Bookmarks
\(a_1\): 2
\(d\): 5
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:42) correct
24%
(02:43)
wrong
based on 292
sessions
History
Date
Time
Result
Not Attempted Yet
An arithmetic sequence is such that the division of the fifth term by the third term gives a quotient of 1 and leaves a remainder of 10, while the product of the first and third terms equals 24.
In the table, select a value for the first term, \(a_{1}\) of the sequence, and a value for the difference, \(d\), between successive terms of the sequence, that together are consistent with the given information. Make only one selection in each column.
In the table, select a value for the first term, \(a_{1}\) of the sequence, and a value for the difference, \(d\), between successive terms of the sequence, that together are consistent with the given information. Make only one selection in each column.
| \(a_1\) | \(d\) | |
| 2 | ||
| 3 | ||
| 5 | ||
| 7 | ||
| 12 | ||
| 22 |
ShowHide Answer
Official Answer
\(a_1\): 2
\(d\): 5
poojaarora1818
Joined: 30 Jul 2019
Last visit: 21 Apr 2026
Posts: 1,619
Own Kudos:
Given Kudos: 3,808
Location: India
Concentration: General Management, Economics
Schools: Duke '27 Haas '27 Kelley '27 Kellogg '27 McDonough '27
GPA: 3
WE:Human Resources (Real Estate)
Products:
27 May 2025, 01:50
Kudos
Bookmarks
Solution:
1. The division of the fifth term by the third term gives a quotient of 1 and leaves a remainder of 10-- 5th term = 1*3rd term + 10
2. The product of the first and third terms equals 24--1st term*3rd term =24.
Let's take the LCM of 24, that is \(2^{3}\)*3. The only term that fits for the third term is 12, and 1st term is 2. So, from here we can conclude the 5th term in the sequence will be 22. Also, we can notice, the common difference between the 1st and 3rd term or the 3rd and 5th term is 10. So, the successive difference between the terms that fits our answer choice is 5.
The answer for the First dropdown is 2, and the Second dropdown is 5.
1. The division of the fifth term by the third term gives a quotient of 1 and leaves a remainder of 10-- 5th term = 1*3rd term + 10
2. The product of the first and third terms equals 24--1st term*3rd term =24.
Let's take the LCM of 24, that is \(2^{3}\)*3. The only term that fits for the third term is 12, and 1st term is 2. So, from here we can conclude the 5th term in the sequence will be 22. Also, we can notice, the common difference between the 1st and 3rd term or the 3rd and 5th term is 10. So, the successive difference between the terms that fits our answer choice is 5.
The answer for the First dropdown is 2, and the Second dropdown is 5.
Bismuth83
27 May 2025, 12:12
Kudos
Bookmarks
\(a_{5}\) = \(a_{1}\) +4d
\(a_{3}\) = \(a_{1}\) + 2d
\(a_{5}\) = \(a_{3}\) + 2d
Given:
\(a_{5}\) = 1*\(a_{3}\) + 10
2d = 10
d=5
\(a_{1}\) * ( \(a_{1}\) + 2d) = 24
\(a_{1}\) * (\(a_{1}\) + 10) = 24
\(a_{1}\) = 2
\(a_{3}\) = \(a_{1}\) + 2d
\(a_{5}\) = \(a_{3}\) + 2d
Given:
\(a_{5}\) = 1*\(a_{3}\) + 10
2d = 10
d=5
\(a_{1}\) * ( \(a_{1}\) + 2d) = 24
\(a_{1}\) * (\(a_{1}\) + 10) = 24
\(a_{1}\) = 2
Bismuth83
