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An employee at a company was given the task of making a large number

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An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 01:40
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An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.

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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 03:45
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Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.



(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

Say copier A produced 2X copies in 5 minutes
Copier B therefore produced X copies in 15 minutes
Copier B produced 2X copies in 30 minutes
therefore,
Copier A could have produced remaining copies in another 5 minutes
total time = 50 minutes

sufficient

(2) Copier B produces 10 copies per minute.
Insufficient.

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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 04:11
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Answer A is correct.

Let rates be Ra and Rb of copying. we can get an equation of relation between of ra and rb from statement 1.

Now question is how much time needed for copying RA?
we have already got an equation 45 mints of ra and 30 mints of rb completes. if we substitute Rb from equation obtained from statement 1, we will get the time required for Ra to complete individually.
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An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 06:19
Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.


I think answer should be D.

from the questions, we can find out the equation of completing the tasks when both the copiers are used.

as in 45/Ra + 30/Rb =1.

Now, statement 1 give a relation between Ra and Rb, so, on substituting Rb with the equivalent value of Ra, we can find out the value of Ra.

Statement 2 directly provides the value of Rb. on substituting Rb value in the above equation, we can find out the value of Ra. Sufficient.

Please correct me if I am missing anything.
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 08:52
abhimahna wrote:
Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.


I think answer should be D.

from the questions, we can find out the equation of completing the tasks when both the copiers are used.

as in 45/Ra + 30/Rb =1.

Now, statement 1 give a relation between Ra and Rb, so, on substituting Rb with the equivalent value of Ra, we can find out the value of Ra.

Statement 2 directly provides the value of Rb. on substituting Rb value in the above equation, we can find out the value of Ra. Sufficient.

Please correct me if I am missing anything.


I don't believe that B is sufficient as we do not know the number of copies which would be produced overall. Knowing that 300 copies were produced after A broke gives no information as to the rate that A was producing copies at beforehand.
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An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 12:55
I think that answer should be E considering wording of the first statement.
It says: Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.
So, it can mean that we only know the rate at which these copiers works for the first 5/15 minutes respectively. The rate can change after the first printer has worked for 5 minutes.
So, either it is E, or question wording is a bit vague, or i overthink the issue:)
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 12:59
Forzafonz wrote:
I think that answer should be E considering wording of the first statement.
It says: Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.
So, it can mean that we only know the rate at which these copiers works for the first 5/15 minutes respectively. The rate can change after first printer has worked for 5 minutes.
So, either it is E, or question wording is a bit vague, or i overthink the issue:)


The copiers were both specified as being constant rates in the original question stem.
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 14:07
DAllison2016 wrote:
Forzafonz wrote:
I think that answer should be E considering wording of the first statement.
It says: Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.
So, it can mean that we only know the rate at which these copiers works for the first 5/15 minutes respectively. The rate can change after first printer has worked for 5 minutes.
So, either it is E, or question wording is a bit vague, or i overthink the issue:)


The copiers were both specified as being constant rates in the original question stem.

Yeah, indeed. My bad. The answer is totally A then..
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 14:21
Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.


(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.
Copier B produces x copies in 15 minutes and 2x copies in 30 mins.

Had the copier A not broken down, this 2x work would have been done by copier A in order to complete the task.

Copier A produces 2x copies in 5 minutes (given information). So had the copier A was working it would have taken 5 more minutes to complete the task. i.e. 50 minutes were taken .

Sufficient.

(2) Copier B produces 10 copies per minute.
No relation between rate of copier A and B is given. Not sufficient.

A is the answer
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 27 Jul 2016, 22:12
abhimahna wrote:
Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.


I think answer should be D.

from the questions, we can find out the equation of completing the tasks when both the copiers are used.

as in 45/Ra + 30/Rb =1.

Now, statement 1 give a relation between Ra and Rb, so, on substituting Rb with the equivalent value of Ra, we can find out the value of Ra.

Statement 2 directly provides the value of Rb. on substituting Rb value in the above equation, we can find out the value of Ra. Sufficient.

Please correct me if I am missing anything.


The relation should be 45*Ra + 30*Rb = total copies
since you don't know the number of total copies, just knowing Rb wont help you get the value of Ra
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 28 Jul 2016, 01:29
answer is A

if copier B produces y copies in 15 min.

rate of B=y/15

so rate of A=2y/5

total no of copies would be 20y produced by A and B

so Only A to produce 20y copies it would take 50 min which is the answer.


2)insuff no relation between A and B


ans-A
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Re: An employee at a company was given the task of making a large number  [#permalink]

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New post 01 Aug 2016, 00:58
1
Bunuel wrote:
An employee at a company was given the task of making a large number of copies. He spent the first 45 minutes making copies at a constant rate on copier A, but copier A broke down before the task was completed. He then spent the next 30 minutes finishing the task on copier B, which also produced copies at a constant rate. How many total minutes would the task have taken had copier A not broken down?

(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.

(2) Copier B produces 10 copies per minute.


(1) Copier A produced twice as many copies in its first 5 minutes of operation as copier B produced in its first 15 minutes.
In 5 minutes A makes = 2x copies
In 45 minutes A will makes = 18x copies

In 15 minutes B makes = x copies
In 30 minutes b will make e= 2x copies

WORK IS FINISHED
Therefore total work that was remaining when A broke down was only 2x
We know that A completed 18x work in 45 minutes
therefore we know it would have completed 2x work in (45/18 )*2 = 5 minutes
SO A would have completed the task in 45 + 5 = 50 minutes
SUFFICIENT

(2) Copier B produces 10 copies per minute.
B produced 30*10 = 300 copies
We do not know how many total copies are there to make:-
Therefore we cannot know how many copies A made:-
therefore we cannot know the rate of A.
therefore we cannot know total time that A would have taken
INSUFFICIENT
ANSWER IS A
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