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ricokevin
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Summer3
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ricokevin
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Summer3
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Yeah, first I did it wrong way...so I got wrong answer but I did it again and got C.

This is what I did:

n = 3q + 2 (q = quotient) then I drew a table (i) for q and n...
t = 5q + 3 again I drew a table(ii) for q and t too

(1) (n-2 / 5) = int ....I checked from the table (i) and found n = 17 fit here..
but from table (ii) any value of t can be taken and remainder will be different..INSUFF

(2) t/3 = int .....from table (ii) t = 18 fits here...but n from table (i) can be any value so different remainders...INSUFF

Taking both (1) and (2) together:
n = 17 and t = 18......we can get the answer...SUFF
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Summer3
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And yes, I rechecked the C by taking another value for n and t, too...e.g. n = 32 from table (i) and t = 63 or even same 18....remainder was same :-)



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