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12 May 2020, 23:50
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An urn contains 10 balls, numbered from 1 to 10. If 2 balls are selected at random with replacement from the urn, what is the probability that the sum of the 2 numbers on the balls will be even?
A. 25%
B. 37.5%
C. 50%
D. 62.5%
E. 75%
Total balls = 10 , Since it says replacement of balls, hence with each ball, there will be 10 possibilities.
Total Possibilities = 10*10 =100
Now,
Even = 2,4,6,8,10 - 05 even nos; Since it says replacement of balls, hence with each ball, there will be 5 possibilities. Total Possibility = 5^2 =25
Odd = 1,3,5,7,9 - 05 odd nos; Since it says replacement of balls, hence with each ball, there will be 5 possibilities.Total Possibility = 5^2 =25
Thus P(A) = (25+25)/100 = 50/100 = 50% (Ans-C)
A. 25%
B. 37.5%
C. 50%
D. 62.5%
E. 75%
Total balls = 10 , Since it says replacement of balls, hence with each ball, there will be 10 possibilities.
Total Possibilities = 10*10 =100
Now,
Even = 2,4,6,8,10 - 05 even nos; Since it says replacement of balls, hence with each ball, there will be 5 possibilities. Total Possibility = 5^2 =25
Odd = 1,3,5,7,9 - 05 odd nos; Since it says replacement of balls, hence with each ball, there will be 5 possibilities.Total Possibility = 5^2 =25
Thus P(A) = (25+25)/100 = 50/100 = 50% (Ans-C)
28 Oct 2025, 00:55
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