kevincan
Analysts expected that 70% of Dorthwood’s eligible voters would vote in a mayoral election and that the leading candidate would receive 45% of the votes cast. In the actual election, the voter participation rate was 5 percentage points higher than expected , and the leading candidate received half of the votes cast. As a result, she received 19,800 more votes than analysts had expected. If 60% of Dorthwood’s residents are eligible voters, how many residents does Dorthwood have?
A. 330,000
B. 450,000
C. 528,000
D. 550,000
E. 629,000
Let the total Dorthworth eligible voters be 100x.
Analyst prediction:
70%*(100x) = 70x will vote.
And leading candidate with secure 45%(70x) votes.
Actual poll day:
5% points increased. So , 75%(100x) = 75x has voted.
The leading candidate secured 50%*(75x) votes.
45%(70x) = ?
10% of 70x = 7. So 40% means 4*7 = 28. And, 5% = 3.5
45% (70x) = 31.5x
50%*(75x) =?
37.5x
Difference 6x = 19800
Therefore x = 3300
100x = 3,30,000.
Finally, Dorthworth eligible voters = 100x = 3,30,000. Which is 60% of total population.
(3/5)* total population = 3,30,000
Total population = 5*(110000) =
5,50,000Option D