Angelo and Isabella are both salespersons. In any given week, Angelo m

Answer A:

\(0.1x=550+0.08*(x-1000)\)
=>
\(0.02x=470\)
=> \(x=23,500\)

A

.1x=550+8%(x-1000)

x=23500

A
550+0.08*(x-1000)=0.1x

Let x be Angelo's and Isabella's weekly sales. Hence we have that Angelo earns 550+0.08(x-1000) and Isabella earns simply 0.1x. Hence we have to solve 550+0.08(x-1000)=0.1x ==> 0.02x=47000 ==>x=23500 Answer A

Answer = (A) 23,500

Let the weekly sales of both = x

\(550 + (x-1000)\frac{8}{100} = \frac{10}{100}x\)

x = 23500

OFFICIAL SOLUTION:

The problem asks for the amount of weekly sales it takes for Angelo and Isabella to earn the same amount of money. You can write an equation that sets Angelo’s and Isabella’s weekly earnings equal to each other, with x representing weekly sales. Weekly earnings for each salesperson equal base salary plus commission. So Angelo’s earnings are 550 + (0.08)(x – 1,000), and Isabella’s are 0.10x. Set up the equation and solve:
550 + (0.08)(x – 1,000) = 0.10x

Distribute the 0.08:
550 + 0.08x – 80 = 0.10x

Combine terms and subtract 0.08x from both sides:
470 = 0.02x

Divide both sides by 0.02:
23,500 = x

Your answer is A.
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oh man..this question is def not a 700 level one...
Angelo makes 550$ + 0.08(X-1000), where X is his sales.
Isabella makes 0.1X - where X is the sales.

we need these two equations to be equal:
550+0.08X-80 = 0.1X
470 = 0.02X | multiply by 100
47000 = 2X
X = 23,500


A

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