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23 Jun 2011, 02:26
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
20% (01:40) correct
80%
(01:33)
wrong
based on 5
sessions
History
Date
Time
Result
Not Attempted Yet
in how many ways can 1260^4 be represented as product of two relatively prime factors?
a. 10
b. 12
c.8
d.6
e.4
it can be done by a formula. will be provide later.
now it's expert's time
a. 10
b. 12
c.8
d.6
e.4
it can be done by a formula. will be provide later.
now it's expert's time
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23 Jun 2011, 02:38
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dimri10
1260^4 = 2^8*3^8*5^4*7^4
The formula is 2^(n-1) for the pair of co primes.
the co primes are 2,3,5,7,
so its 2^4-1 = 2^3 = 8
23 Jun 2011, 03:09
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dimri10
I didn't know the formula:
We have 4 prime factors. Thus, the number of co-primes should be:
\(C^4_1+\frac{C^4_2}{2}+1=8\)
