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Bunuel
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Bunuel
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aashi1
Current price = $3,600

1) Price increased by 10%. Say the price 2 years ago is p

So, \(\frac{3600-p}{p} = \frac{10}{100}\)

p can be determined from here. Hence, sufficient.

2) Price today is 1.21 times before 2 years. Say the price 2 years ago is p

So, 3600 = 1.21p

p can be determined from here. Hence, sufficient.

Hence, D
1 is sufficient but it's compounding so would be 21/100
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Hi, I am new to this club. I am not able to see the options for the DS questions. Can someone please help me.. Thank you
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I'm not sure I understand the math, how does 3600-2/2= 10/100?
aashi1
Current price = $3,600

1) Price increased by 10%. Say the price 2 years ago is p

So, \(\frac{3600-p}{p} = \frac{10}{100}\)

p can be determined from here. Hence, sufficient.

2) Price today is 1.21 times before 2 years. Say the price 2 years ago is p

So, 3600 = 1.21p

p can be determined from here. Hence, sufficient.

Hence, D
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There's a formula for percent change (in this case they give you it: 10%)

the formula is:
% change = \(\frac{ final price - initial price }{ initial price}\) * 100

using the equation we get...
p = initial price
\(\frac{3600 - p}{p}\)* 100 = 10%
\(\frac{3600 - p}{p}\) = 10/100
and since p is the only variable, you can solve for p :) aka sufficient
vfost906
I'm not sure I understand the math, how does 3600-2/2= 10/100?
aashi1
Current price = $3,600

1) Price increased by 10%. Say the price 2 years ago is p

So, \(\frac{3600-p}{p} = \frac{10}{100}\)

p can be determined from here. Hence, sufficient.

2) Price today is 1.21 times before 2 years. Say the price 2 years ago is p

So, 3600 = 1.21p

p can be determined from here. Hence, sufficient.

Hence, D
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x now = (10%)*2*X old
X old = X now /1.2
X now : 3600 $
X old is Ok
State 1 is sufficient

X now = 1.21 X old
X old = X now /1.21
X now : 3600 $
X old is Ok
State 2 is sufficient

Bunuel
If today the price of an item is $3,600, what was the price of the item exactly 2 years ago?

(1) The price of the item increased by 10 per-cent per year during this 2-year period.
(2) Today the price of the item is 1.21 times its price exactly 2 years ago.
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The first formula needs to be iterated twice:

(3600 - p)/p *100 = 10 -> p = 3272.7 It's the value one year ago
(3272.7 - p)/p *100 = 10 -> p = 2975.18 It's the value two years ago

As proof tha calculation of the second formula matches:

3600 = 1.21p -> p = 2975.21

Bunuel
If today the price of an item is $3,600, what was the price of the item exactly 2 years ago?

(1) The price of the item increased by 10 per-cent per year during this 2-year period.
(2) Today the price of the item is 1.21 times its price exactly 2 years ago.
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Hi Pav,
These will always be the answers and they will always be in this order.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.
pav2305
Hi, I am new to this club. I am not able to see the options for the DS questions. Can someone please help me.. Thank you
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