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27 Aug 2018, 11:09
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:06) correct
18%
(01:25)
wrong
based on 89
sessions
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Any decimal that has only a finite number of nonzero digits is a terminating decimal. For example, 25, 0.09, and 8.072 are three terminating decimals. If p and q are positive integers and the ratio
\(\frac{p}{q}\) is expressed as a decimal, is \(\frac{p}{q}\) a terminating decimal?
(1) q is a prime number less than 10.
(2) q is not equal to 3 or 7.
\(\frac{p}{q}\) is expressed as a decimal, is \(\frac{p}{q}\) a terminating decimal?
(1) q is a prime number less than 10.
(2) q is not equal to 3 or 7.
27 Aug 2018, 14:13
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carcass
Question stem:- Is \(\frac{p}{q}\) a terminating decimal?
St1:- q is a prime number less than 10.
Possible value of q: 2, 3 , 5, 7
Terminating decimal: \(\frac{p}{2}\), \(\frac{p}{5}\)
Non-terminating decimal:\(\frac{p}{3}\), \(\frac{p}{7}\)
Question stem is inconsistent.
Insufficient.
St2:- q is not equal to 3 or 7
a) When \(q=2^x*5^y\) (where x and y are non-negative integers), then the ratio \(\frac{p}{q}\) is a terminating decimal.
e.g., q=2,5,4,8,10 etc
b) When q=9, 11, 13 etc. , then the ratio \(\frac{p}{q}\) is NOT a terminating decimal.
Insufficient.
Combined, q<10, q is prime(Primes are +ve), and \(q\neq{3}\) or \(q\neq{7}\)
Possible values of q: \(2(=2^1*5^0)\) and \(5(=2^0*5^1)\)
Since the denominator q is in the form \(2^x*5^y\), hence the ratio \(\frac{p}{q}\) is a terminating decimal..
Sufficient.
Ans. (C)
28 Aug 2018, 04:32
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