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04 Oct 2007, 00:54
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Are all angles of triangle ABC smalled than 90 degrees?
1) 2*AB = 3*BC = 4*AC
2) AC^2 + AB^2 = BC^2
Pls. explain.
1) 2*AB = 3*BC = 4*AC
2) AC^2 + AB^2 = BC^2
Pls. explain.
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04 Oct 2007, 05:11
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1) SUFF
from pythagoras we know that triangle with sides 3,4 and 5 is rectangular
here we have (picking numbers) 6,4 and 3
6 > 5 -> angle is greater than 90
2) pythagoras: SUFF
not really a structured explanation but I hope this will clarify
from pythagoras we know that triangle with sides 3,4 and 5 is rectangular
here we have (picking numbers) 6,4 and 3
6 > 5 -> angle is greater than 90
2) pythagoras: SUFF
not really a structured explanation but I hope this will clarify
04 Oct 2007, 06:52
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statement I
2*AB = 3*BC = 4*AC
Since the sum on angles in triangle is 180 then the ratio of degrees is 180/9 = 20
2*20:3*20:4*20 = 40:60:80
sufficient
statement II
In order for all the angles of the triangle ABC be smaller than 90 degrees you cannot have a right angle. If you did then you could express the ratio of this triangle sides by the Pythagoras Theorem A^2+B^2 = C^2.
AC^2 + AB^2 = BC^2
Comply with Pythagoras Theorem. At least one angle is at 90 degrees.
sufficient
the answer is (D)
2*AB = 3*BC = 4*AC
Since the sum on angles in triangle is 180 then the ratio of degrees is 180/9 = 20
2*20:3*20:4*20 = 40:60:80
sufficient
statement II
In order for all the angles of the triangle ABC be smaller than 90 degrees you cannot have a right angle. If you did then you could express the ratio of this triangle sides by the Pythagoras Theorem A^2+B^2 = C^2.
AC^2 + AB^2 = BC^2
Comply with Pythagoras Theorem. At least one angle is at 90 degrees.
sufficient
the answer is (D)
