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Are the integers p, q, r in an arithmetic progression? (1) q = p*r

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Are the integers p, q, r in an arithmetic progression? (1) q = p*r  [#permalink]

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New post 17 Jan 2019, 21:05
2
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

44% (01:45) correct 56% (01:47) wrong based on 36 sessions

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Are the integers p, q, r in an arithmetic progression?

(1) q = p*r

(2) q = p + r
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Re: Are the integers p, q, r in an arithmetic progression? (1) q = p*r  [#permalink]

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New post 17 Jan 2019, 21:16
If p, q and r are in AP, then q = p+r/2

From statement 1:

q = p*r
Hence p, q and r are not in AP.
Sufficient.

From statement 2:

q = p+r
Again, p, q, and r are not in AP.
Sufficient.

D is the answer.
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Are the integers p, q, r in an arithmetic progression? (1) q = p*r  [#permalink]

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New post 18 Feb 2019, 13:40
Can someone explain the OA?
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Re: Are the integers p, q, r in an arithmetic progression? (1) q = p*r  [#permalink]

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New post 18 Feb 2019, 13:50
1
The question doesn't make much sense, so it's not worth worrying about - it's not even clear what it means (do we need p, q and r to be in progression in that order?) Nor do you even need to know what the phrase "arithmetic progression" means for the GMAT. But it's certainly possible that p=q=r=0 here, and 0, 0, 0 is an arithmetic progression, so the answer using both statements is "possibly yes". But it's also "possibly no", since we could have q = 4 and p=r=2.
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Re: Are the integers p, q, r in an arithmetic progression? (1) q = p*r   [#permalink] 18 Feb 2019, 13:50
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Are the integers p, q, r in an arithmetic progression? (1) q = p*r

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