Hello!
I was playing with the following question:
If the area of the outer square is 4x^2, then the area of the inner square is?
What I did was assume x = 2, so that would make the big square have an area of 16 (4x4).
Since the circle is touching, the diameter must be 4 as well, or a radius of 2. Since the Square is inside the circle, I figured it could be bisected to create two triangles of 45-45-90. The hypotenuse would have to be the radius, which is 2. But since it is a 45-45-90 triangle, I decided that...
2 = x√2 and x is then equal to (2√2)/2.
I multiplied that by itself and divided by 2 to get the area of one triangle. You can multiply that again and get another area to complete the square.
Make a long story short, none of the answers lined up with my whacky math. Does anyone have any insight to my issue?
Thanks
I figured